Quiz Discussion

The square root of \(\frac{{0.342 \times 0.684}}{{0.000342 \times 0.000171}} = ?\)

• 1] 250
• 2] 2500
• 3] 2000
• 4] 4000

\(\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}}\)      = ?

• 1] 0.27
• 2] 0.4087
• 3] 0.73
• 4] 1

When \(\left( {\frac{1}{2} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6}} \right) \) is divided by \(\left( {\frac{2}{5} - \frac{5}{9} + \frac{3}{5} - \frac{7}{{18}}} \right)\) then the result is = ?

• 1]

  \({ \text{5}}\frac{1}{{10}}\)

• 2]

  \({ \text{2}}\frac{1}{{18}}\)

• 3]

  \({ \text{3}}\frac{1}{6}\)

• 4]

  \({ \text{3}}\frac{3}{{10}}\)

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

• 1]

  \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

• 2]

  \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

• 3]

  \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

• 4]

  \(\frac{{{a^2} - {b^2}}}{{ab}}\)

\({{{{(469 + 174)}^2} - {{(469 - 174)}^2}} \over {(469 \times 174)}} = ?\)

• 1] 1
• 2] 4
• 3] 295
• 4] 643

If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \)    then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\)   = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

\(\frac{{225}}{{836}} \times \frac{{152}}{{245}} \div 1\frac{{43}}{{77}} = ?\)

• 1]

  6/49

• 2]

  6/11

• 3]

  3/28

• 4]

  1/7

• 5]

  None of these

Direction: In the question given below the given mathematical symbols are changed from '+' to '÷', '-' to '×', '÷' to '-' and from '×' to '+', then choose your answers from the following options.

• 1] -13
• 2] -3
• 3] 4
• 4] 7

24.962 ÷ (34.11 ÷ 20.05) + 67.96 - 89.11 = ?

• 1] 884
• 2] 346
• 3] 252
• 4] 424
• 5] 366

If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ?

• 1] 0
• 2] 6xyz
• 3] 12xyz
• 4] xyz