Quiz Discussion

If 37/13 =   where x,y,z are natural member , then find x+y+z are:-

Course Name: Quantitative Aptitude

  • 1]

    6

  • 2]

    7

  • 3]

    8

  • 4]

    9

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If \(\left( {x - \frac{1}{x}} \right){ \text{ = }}\sqrt {21} { \text{,}} \)    then the value of \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right) \left( {x + \frac{1}{x}} \right)\) is = ?

 

  • 1] 42
  • 2] 63
  • 3] 115
  • 4] 120
  • 5] 125
Solution
2
Discuss

The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?

  • 1] Rs. 325285
  • 2] Rs. 439355
  • 3] Rs. 550000
  • 4] Cannot be determined
  • 5] None of these
Solution
3
Discuss

The value (1001)3 is = ?

  • 1] 1003003001
  • 2] 100303001
  • 3] 100300301
  • 4] 103003001
Solution
4
Discuss

\(6\frac{5}{6} \times 5\frac{1}{3} \times 17\frac{2}{3} \times 4\frac{1}{2} = ?\)

 

  • 1]

    \(112\frac{1}{3}\)

  • 2]

    \(116\frac{2}{3}\)

  • 3]

    240

  • 4]

    663

  • 5]

    None of these

Solution
5
Discuss

If \(\left( {a + \frac{1}{a}} \right) = 6,    then \left( {{a^4} + \frac{1}{{{a^4}}}} \right)\)   = ?

 

  • 1] 1154
  • 2] 1158
  • 3] 1160
  • 4] 1164
Solution
6
Discuss

There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

  • 1] 20
  • 2] 80
  • 3] 100
  • 4] 200
  • 5] None of these
Solution
7
Discuss

Solve this 9 3/7 - 6 4/7 - ? = 14 4/7

  • 1]

    3/7

  • 2]

    4/7

  • 3]

  • 4]

Solution
8
Discuss

\(\frac{{{{\left( {3\frac{2}{3}} \right)}^2} - {{\left( {2\frac{1}{2}} \right)}^2}}}{{{{\left( {4\frac{3}{4}} \right)}^2} - {{\left( {3\frac{1}{3}} \right)}^2}}}\div\frac{{3\frac{2}{3} - 2\frac{1}{2}}}{{4\frac{3}{4} - 3\frac{1}{3}}}\)   = ?

 

  • 1]

    37/97

  • 2]

    74/97

  • 3]

    \(1\frac{{23}}{{74}}\)

  • 4]

    None of these

Solution
9
Discuss

Let 0 < x < 1, then the correct inequality is = ?

  • 1]

    \(x < \sqrt x < {x^2}\)

  • 2]

    \(\sqrt x < x < {x^2}\)

  • 3]

    \({x^2} < x < \sqrt x \)

  • 4]

    \(\sqrt x < {x^2} < x\)

Solution
10
Discuss

Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \)   = (?)3 + 141

 

  • 1] 5√5
  • 2] (125)2
  • 3] 25
  • 4] 5
  • 5] None of these
Solution
# Quiz