Quiz Discussion

Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by:

• 1]

  1/7

• 2]

  1/8

• 3]

  1/9

• 4]

  7/8

• 5]

  None of these

\(\frac{3}{2} \times \frac{{11}}{5} \div \left( {\frac{{25}}{{44}} \times \frac{{11}}{5}} \right) \div \frac{{33}}{{15}} = ?\)

• 1]

  1/2

• 2]

  2/3

• 3]

  126/125

• 4]

  \(5\frac{{101}}{{125}}\)

• 5]

  None of these

\(\frac{{225}}{{836}} \times \frac{{152}}{{245}} \div 1\frac{{43}}{{77}} = ?\)

• 1]

  6/49

• 2]

  6/11

• 3]

  3/28

• 4]

  1/7

• 5]

  None of these

The value of \({ \text{5}}\frac{1}{3} \div 1\frac{2}{9} \times \frac{1}{4}  \left( {10 + \frac{3}{{1 - \frac{1}{5}}}} \right)\)   = ?

• 1]

  15

• 2]

  67/25

• 3]

  128/11

• 4]

  128/99

If \( \left( {x + \frac{1}{x}} \right){ \text{ = }}\sqrt {13} { \text{,}} \)    then the value of \(\left( {{x^3} - \frac{1}{{{x^3}}}} \right)\)  is = ?

• 1] 26
• 2] 27
• 3] 30
• 4] 36

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

Solve 4376 + 3209 - 1784 + 97 = 3125 + ?

• 1] 2713
• 2] 2743
• 3] 2773
• 4] 2793
• 5] 2737

If \(x = \sqrt 3 { \text{ + }}\sqrt 2 { \text{,}}   \) then the value of \({x^3} - \frac{1}{{{x^3}}}\)  is?

• 1]

  \(10\sqrt 2 \)

• 2]

  \(14\sqrt 2\)

• 3]

  \(22\sqrt 2\)

• 4]

  \(8\sqrt 2\)

The difference of \({ \text{1}}\frac{3}{{16}}\) and its reciprocal is equal to = ?

• 1]

  \(1\frac{1}{8}\)

• 2]

  4/3

• 3]

  15/16

• 4]

  None of these

The expression \(\frac{1}{{x - 1}} - \frac{1}{{x + 1}} - \frac{2}{{{x^2} + 1}} - \frac{4}{{{x^4} + 1}}\)  is equal to = ?

• 1]

  \(\frac{8}{{{x^8} + 1}}\)

• 2]

  \(\frac{8}{{{x^8} - 1}}\)

• 3]

  \(\frac{8}{{{x^7} - 1}}\)

• 4]

  \(\frac{8}{{{x^7} + 1}}\)