Quiz Discussion

What number must be added to the expression 16a2 - 12a to make a perfect square ?

Course Name: Quantitative Aptitude

  • 1]

    9/4

  • 2]

    11/2

  • 3]

    13/2

  • 4]

    16

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If 37/13 =   where x,y,z are natural member , then find x+y+z are:-

  • 1]

    6

  • 2]

    7

  • 3]

    8

  • 4]

    9

Solution
2
Discuss

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

  • 1] 2
  • 2] 3
  • 3] 6
  • 4] 5
Solution
3
Discuss

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

  • 1]

    3ad

  • 2]

    3ac

  • 3]

    2ad

  • 4]

    2ab

Solution
4
Discuss

If a - b = 3 and a2 + b2 = 29, find the value of ab = ?

  • 1] 10
  • 2] 12
  • 3] 15
  • 4] 18
Solution
5
Discuss

\(\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}\)           is equal to = ?

 

  • 1] 24
  • 2] 32
  • 3] 44
  • 4] 100
Solution
6
Discuss

\(1\frac{3}{4} - 1\frac{1}{5} + 1\frac{5}{8} = ?\)

 

  • 1]

    \(2\frac{7}{{40}}\)

  • 2]

    \(3\frac{7}{{40}}\)

  • 3]

    \(9\frac{5}{8}\)

  • 4]

    \(10\frac{7}{8}\)

  • 5]

    None of these

Solution
7
Discuss

Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)

 

  • 1]

    \(4\frac{1}{2}\)

  • 2]

    \(4\frac{1}{6}\)

  • 3]

    \(9\frac{1}{2}\)

  • 4]

    \(\frac{2}{9}\)

Solution
8
Discuss

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

 

  • 1]

    100

  • 2]

    200/101

  • 3]

    200

  • 4]

    202/100

Solution
9
Discuss

\(\left( {x + \frac{1}{x}} \right)\left( {x - \frac{1}{x}} \right)\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\left( {{x^2} + \frac{1}{{{x^2}}} + 1} \right)\)   is equal to ?

 

  • 1]

    \({x^6} - \frac{1}{{{x^6}}}\)

  • 2]

    \({x^8} - \frac{1}{{{x^8}}}\)

  • 3]

    \({x^6} + \frac{1}{{{x^6}}}\)

  • 4]

    \({x^8} + \frac{1}{{{x^8}}}\)

Solution
10
Discuss

3.325 + 3.012 + 0.660 + 31.151 + 0.251 = ?

  • 1]

    40.019

  • 2]

    35.055

  • 3]

    37.514

  • 4]

    38.399

Solution
# Quiz