The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
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Find the value of \(\frac{{{{\left( {0.75} \right)}^3}}}{{1 - 0.75}} + \left[ {0.75 + {{\left( {0.75} \right)}^2} + 1} \right]\)
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2
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The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)
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3
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572.0 / 26 * 12 – 200 = (2)^x
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4
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52 + 132 – 112 = (?)3 – 52
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5
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Number of digits in the square root of 62478078 is = ?
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6
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\(\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}}\)
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7
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If the expression \({ \text{2}}\frac{1}{2}{ \text{ of }}\frac{3}{4} \times \frac{1}{2} \div \frac{3}{2} + \frac{1}{2} \div \frac{3}{2}\left[ {\frac{2}{3} - \frac{1}{2}{ \text{ of }}\frac{2}{3}} \right]\) is simplified, we get -
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8
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If \(\frac{a}{b}{ \text{ + }}\frac{b}{a}{ \text{ = 2,}}\) then the value of (a - b) is = ?
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9
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Evaluate : \(\frac{{\left( {923 - 347} \right)}}{?} = 32\)
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10
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Simplification of \(\frac{{{{\left( {3.4567} \right)}^2} - {{\left( {3.4533} \right)}^2}}}{{0.0034}} = ?\)
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