Quiz Discussion

A millionaire bought a lot of hats 1/4 of which were brown. The millionaire sold 2/3 of the including 4/5 of the brown hats. What fraction of the unsold hats were brown ?

 

Course Name: Quantitative Aptitude

  • 1]

    1/60

  • 2]

    1/15

  • 3]

    3/20

  • 4]

    3/5

  • 5]

    3/4

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If \(\frac{1}{3} + \frac{1}{2} + \frac{1}{x}{ \text{ = 4}}\)     then x = ?

 

  • 1]

    5/16

  • 2]

    6/19

  • 3]

    18/5

  • 4]

    24/11

Solution
2
Discuss

\(\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}}\)

 

  • 1] 0.1
  • 2] 10
  • 3] 102
  • 4] 103
Solution
3
Discuss

3.325 + 3.012 + 0.660 + 31.151 + 0.251 = ?

  • 1]

    40.019

  • 2]

    35.055

  • 3]

    37.514

  • 4]

    38.399

Solution
4
Discuss

Find the value of \(\sqrt {248 + \sqrt {52 + \sqrt {144} } } = ?\)

 

  • 1]

    -16

  • 2]

    \(\pm 16\)

  • 3]

    16

  • 4]

    16.2

Solution
5
Discuss

Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)

 

  • 1]

    1/2

  • 2]

    4

  • 3]

    2

  • 4]

    1/4

Solution
6
Discuss

(? - 968) / 79 * 4 = 512

 

  • 1] 10185
  • 2] 10190
  • 3] 11075
  • 4] 11080
  • 5] None of these
Solution
7
Discuss

1 - [5 - {2 + (- 5 + 6 - 2) 2}] is equal to:

  • 1] -4
  • 2] 2
  • 3] 0
  • 4] 2
Solution
8
Discuss

\(\frac{3}{2} \times \frac{{11}}{5} \div \left( {\frac{{25}}{{44}} \times \frac{{11}}{5}} \right) \div \frac{{33}}{{15}} = ?\)

 

  • 1]

    1/2

  • 2]

    2/3

  • 3]

    126/125

  • 4]

    \(5\frac{{101}}{{125}}\)

  • 5]

    None of these

Solution
9
Discuss

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

 

  • 1]

    \(1\frac{{11}}{{17}}\)

  • 2]

    \(1\frac{{5}}{{7}}\)

  • 3]

    \(1\frac{{6}}{{17}}\)

  • 4]

    \(1\frac{{21}}{{17}}\)

Solution
10
Discuss

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

 

  • 1]

    \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

  • 2]

    \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

  • 3]

    \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

  • 4]

    \(\frac{{{a^2} - {b^2}}}{{ab}}\)

Solution
# Quiz