If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

Direction: In the question given below the given mathematical symbols are changed from '+' to '÷', '-' to '×', '÷' to '-' and from '×' to '+', then choose your answers from the following options.

• 1] -13
• 2] -3
• 3] 4
• 4] 7

\(\frac{{225}}{{836}} \times \frac{{152}}{{245}} \div 1\frac{{43}}{{77}} = ?\)

• 1]

  6/49

• 2]

  6/11

• 3]

  3/28

• 4]

  1/7

• 5]

  None of these

If \(\left( {{a^4} + \frac{1}{{{a^4}}}} \right){ \text{ = 1154,}}\)     then the value of \(\left( {{a^3} + \frac{1}{{{a^3}}}} \right)\)   is = ?

• 1] 198
• 2] 200
• 3] 216
• 4] None of these

\(1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{7} + \frac{1}{{14}} + \frac{1}{{28}}\)     is equal to = ?

• 1] 2
• 2] 2.5
• 3] 3
• 4] 3.5

Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by:

• 1]

  1/7

• 2]

  1/8

• 3]

  1/9

• 4]

  7/8

• 5]

  None of these

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

• 1] 2
• 2] 3
• 3] 6
• 4] 5

Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)

• 1]

  1/2

• 2]

  4

• 3]

  2

• 4]

  1/4

Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \)   = (?)3 + 141

• 1] 5√5
• 2] (125)2
• 3] 25
• 4] 5
• 5] None of these

Simplify : \(1 - \left[ {1 - \left\{ {1 - \left( {1 - \overline {1 - 1} } \right)} \right\}} \right]\)

• 1] 0
• 2] 1
• 3] 2
• 4] 3
• 5] None of these