Quiz Discussion

The sum of \(\sqrt {0.01} + \sqrt {0.81} + \sqrt {1.21} + \sqrt {0.0009} = ?\)

 

Course Name: Quantitative Aptitude

  • 1] 2.1
  • 2] 2.13
  • 3] 2.03
  • 4] 2.11
Solution
No Solution Present Yet

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# Quiz
1
Discuss

(36.14)^2 – (21.28)^2 =?

  • 1]

    850

  • 2]

    860

  • 3]

    865

  • 4]

    853

Solution
2
Discuss

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

 

  • 1]

    \(1\frac{{11}}{{17}}\)

  • 2]

    \(1\frac{{5}}{{7}}\)

  • 3]

    \(1\frac{{6}}{{17}}\)

  • 4]

    \(1\frac{{21}}{{17}}\)

Solution
3
Discuss

5907 – 1296 / 144 = x * 8.0

  • 1]

    700.05

  • 2]

    705.25

  • 3]

    751.54

  • 4]

    737.25

Solution
4
Discuss

The value of \(\frac{{{x^2} - {{\left( {y - z} \right)}^2}}}{{{{\left( {x + z} \right)}^2} - {y^2}}}{ \text{ + }}\frac{{{y^2} - {{\left( {x - z} \right)}^2}}}{{{{\left( {x + y} \right)}^2} - {z^2}}} +\frac{{{z^2} - {{\left( {x - y} \right)}^2}}}{{{{\left( {y + z} \right)}^2} - {x^2}}}\)   is = ?

 

  • 1] -1
  • 2] 0
  • 3] 1
  • 4] None of these
Solution
5
Discuss

Let 0 < x < 1, then the correct inequality is = ?

  • 1]

    \(x < \sqrt x < {x^2}\)

  • 2]

    \(\sqrt x < x < {x^2}\)

  • 3]

    \({x^2} < x < \sqrt x \)

  • 4]

    \(\sqrt x < {x^2} < x\)

Solution
6
Discuss

25 * 3.250 + 50.40 / 24.0 = ?

  • 1]

    75

  • 2]

    80

  • 3]

    77

  • 4]

    83

Solution
7
Discuss

If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

 

  • 1]

    10/3

  • 2]

    82/9

  • 3]

    7

  • 4]

    11

Solution
8
Discuss

\(\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}\)           is equal to = ?

 

  • 1] 24
  • 2] 32
  • 3] 44
  • 4] 100
Solution
9
Discuss

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

 

  • 1]

    100

  • 2]

    200/101

  • 3]

    200

  • 4]

    202/100

Solution
10
Discuss

64^12 / 4^15 = 64^x

  • 1]

    6

  • 2]

    5

  • 3]

    4

  • 4]

    7

Solution
# Quiz