Quiz Discussion

\(\frac{{{{\left( {a - b} \right)}^2} - {{\left( {a + b} \right)}^2}}}{{ - 4a}}{ \text{ = }}\frac{x}{y}\)     On simplifying the given equations, which of the following equations will be obtained ?

• 1] xy = b
• 2] bx = y
• 3] ab = x
• 4] yb = x
• 5] ay = x

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

• 1]

  \(17\frac{5}{{12}}\)

• 2]

  \(17\frac{8}{{17}}\)

• 3]

  \(20\frac{3}{{25}}\)

• 4]

  \(20\frac{{103}}{{250}}\)

Simplify : \(\frac{{ - \frac{1}{2} - \frac{2}{3} + \frac{4}{5} - \frac{1}{3} + \frac{1}{5} + \frac{3}{4}}}{{\frac{1}{2} + \frac{2}{3} - \frac{4}{3} + \frac{1}{3} - \frac{1}{5} - \frac{4}{5}}}\)

• 1]

  -3/10

• 2]

  -10/3

• 3]

  -2

• 4]

  1

Solve \({ \text{1}}\frac{4}{5} + 20 - 280 \div 25 = ?\)

• 1]

  \(8\frac{1}{5}\)

• 2]

  \(9\frac{1}{2}\)

• 3]

  \(11\frac{1}{2}\)

• 4]

  \(10\frac{3}{5}\)

• 5]

  \(12\frac{1}{5}\)

\(\left( {x + \frac{1}{x}} \right)\left( {x - \frac{1}{x}} \right)\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\left( {{x^2} + \frac{1}{{{x^2}}} + 1} \right)\)   is equal to ?

• 1]

  \({x^6} - \frac{1}{{{x^6}}}\)

• 2]

  \({x^8} - \frac{1}{{{x^8}}}\)

• 3]

  \({x^6} + \frac{1}{{{x^6}}}\)

• 4]

  \({x^8} + \frac{1}{{{x^8}}}\)

If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

• 1]

  10/3

• 2]

  82/9

• 3]

  7

• 4]

  11

Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?

• 1] a
• 2] b
• 3] c
• 4] All equal

\(\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}}\)

• 1] 0.1
• 2] 10
• 3] 102
• 4] 103

\(1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{7} + \frac{1}{{14}} + \frac{1}{{28}}\)     is equal to = ?

• 1] 2
• 2] 2.5
• 3] 3
• 4] 3.5

1 - [5 - {2 + (- 5 + 6 - 2) 2}] is equal to:

• 1] -4
• 2] 2
• 3] 0
• 4] 2