There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
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1
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Solve : 128.43 + 30.21 + ? = 173
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2
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Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)
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3
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The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?
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4
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572.0 / 26 * 12 – 200 = (2)^x
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5
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Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)
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6
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The square root of \(\frac{{0.342 \times 0.684}}{{0.000342 \times 0.000171}} = ?\)
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7
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A teacher wants to arrange his students in an equal number of rows and columns. If there are 1369 students, the number of students in the last row are ?
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8
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\(1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{7} + \frac{1}{{14}} + \frac{1}{{28}}\) is equal to = ?
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9
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\(1\frac{3}{4} - 1\frac{1}{5} + 1\frac{5}{8} = ?\)
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10
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If the expression \({ \text{2}}\frac{1}{2}{ \text{ of }}\frac{3}{4} \times \frac{1}{2} \div \frac{3}{2} + \frac{1}{2} \div \frac{3}{2}\left[ {\frac{2}{3} - \frac{1}{2}{ \text{ of }}\frac{2}{3}} \right]\) is simplified, we get -
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