Quiz Discussion

There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

Course Name: Quantitative Aptitude

  • 1] 20
  • 2] 80
  • 3] 100
  • 4] 200
  • 5] None of these
Solution
No Solution Present Yet

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# Quiz
1
Discuss

The simplification of \(\frac{5}{{3 + \frac{3}{{1 - \frac{2}{3}}}}}, = ?\)

 

  • 1]

    5

  • 2]

    5/3

  • 3]

    5/12

  • 4]

    3/4

Solution
2
Discuss

\(6\frac{5}{6} \times 5\frac{1}{3} \times 17\frac{2}{3} \times 4\frac{1}{2} = ?\)

 

  • 1]

    \(112\frac{1}{3}\)

  • 2]

    \(116\frac{2}{3}\)

  • 3]

    240

  • 4]

    663

  • 5]

    None of these

Solution
3
Discuss

( √5 – 2)^2 = x – √80

  • 1]

    9

  • 2]

    7

  • 3]

    6

  • 4]

    10

Solution
4
Discuss

Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?

  • 1] a
  • 2] b
  • 3] c
  • 4] All equal
Solution
5
Discuss

Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \)   = (?)3 + 141

 

  • 1] 5√5
  • 2] (125)2
  • 3] 25
  • 4] 5
  • 5] None of these
Solution
6
Discuss

Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)

 

  • 1]

    \(4\frac{1}{2}\)

  • 2]

    \(4\frac{1}{6}\)

  • 3]

    \(9\frac{1}{2}\)

  • 4]

    \(\frac{2}{9}\)

Solution
7
Discuss

\(1888 \div 32 \div 8 = ?\)

 

  • 1] 7.375
  • 2] 9.485
  • 3] 29.5
  • 4] 472
  • 5] None of these
Solution
8
Discuss

If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

 

  • 1]

    10/3

  • 2]

    82/9

  • 3]

    7

  • 4]

    11

Solution
9
Discuss

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

 

  • 1] 0
  • 2] 1
  • 3] 3
  • 4] 9
Solution
10
Discuss

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

 

  • 1]

    \(17\frac{5}{{12}}\)

  • 2]

    \(17\frac{8}{{17}}\)

  • 3]

    \(20\frac{3}{{25}}\)

  • 4]

    \(20\frac{{103}}{{250}}\)

Solution
# Quiz