If a - b = 3 and a2 + b2 = 29, find the value of ab = ?
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(9.0 / 2 * 27 / 9 ) / (18/7.5 * 5.0 / 4) = ?
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Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)
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Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)
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4
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1559.95 - 7.99 × 24.96 - ?2 = 1154
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5
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The simplified value of
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6
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\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\) Find the value in place of (?)
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7
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Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)
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If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\) + \(\sqrt {{ \text{0}}{ \text{.4096}}}\) + \(\sqrt {{ \text{0}}{ \text{.004096}}}\) + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\) up to two place of decimals is = ?
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The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
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If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\) and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\) where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\) is equal to = ?
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