Quiz Discussion

Simplify : \(\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times  2\sqrt {3\frac{1}{9}}\)   = ?

• 1]

  45/256

• 2]

  \(1\frac{{17}}{{28}}\)

• 3]

  \(4\frac{3}{8}\)

• 4]

  \(2\frac{3}{{16}}\)

Solve 4376 + 3209 - 1784 + 97 = 3125 + ?

• 1] 2713
• 2] 2743
• 3] 2773
• 4] 2793
• 5] 2737

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9

853 + ? / 17 = 1000

• 1] 2482
• 2] 2499
• 3] 2516
• 4] 16147
• 5] None of these

5907 – 1296 / 144 = x * 8.0

• 1]

  700.05

• 2]

  705.25

• 3]

  751.54

• 4]

  737.25

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

• 1] 2
• 2] 3
• 3] 6
• 4] 5

The value of \(\frac{{{{\left( {x - y} \right)}^3} + {{\left( {y - z} \right)}^3} + {{\left( {z - x} \right)}^3}}}{{{{\left( {{x^2} - {y^2}} \right)}^3} + {{\left( {{y^2} - {z^2}} \right)}^3} + {{\left( {{z^2} - {x^2}} \right)}^3}}}\)       is = ?

• 1]

  0

• 2]

  1

• 3]

  \({\left[ {2\left( {x + y + z} \right)} \right]^{ - 1}}\)

• 4]

  \({\left[ {\left( {x + y} \right)\left( {y + z} \right)\left( {z + x} \right)} \right]^{ - 1}}\)

If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

• 1]

  10/3

• 2]

  82/9

• 3]

  7

• 4]

  11

\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \)     is equal to = ?

• 1] 1
• 2] 4
• 3] 3
• 4] 2

\(\frac{3}{2} \times \frac{{11}}{5} \div \left( {\frac{{25}}{{44}} \times \frac{{11}}{5}} \right) \div \frac{{33}}{{15}} = ?\)

• 1]

  1/2

• 2]

  2/3

• 3]

  126/125

• 4]

  \(5\frac{{101}}{{125}}\)

• 5]

  None of these