The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?
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Simplify : \(\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?\)
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2
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\(\frac{{ \root 3 \of 8 }}{{\sqrt {16} }} \div \sqrt {\frac{{100}}{{49}}} \times \root 3 \of {125} \) is equal to = ?
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3
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Assume that \(\sqrt {13} \) = 3.605(approximately) and \(\sqrt {130}\) = 11.40(approximately) Find the value of: \(\sqrt {1.3}\) + \(\sqrt {1300}\) + \(\sqrt {0.013}\)
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4
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\(1 + \frac{1}{2} + \frac{1}{4} + \frac{1}{7} + \frac{1}{{14}} + \frac{1}{{28}}\) is equal to = ?
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5
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200 ÷ 25 × 4 + 12 - 3 = ?
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6
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\(\frac{{{{\left( {3\frac{2}{3}} \right)}^2} - {{\left( {2\frac{1}{2}} \right)}^2}}}{{{{\left( {4\frac{3}{4}} \right)}^2} - {{\left( {3\frac{1}{3}} \right)}^2}}}\div\frac{{3\frac{2}{3} - 2\frac{1}{2}}}{{4\frac{3}{4} - 3\frac{1}{3}}}\) = ?
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7
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Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by:
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8
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(4 / 5) × ? × (3 / 7) = (16 / 105)
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9
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4848 / 24 * 11 - 222 = ?
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10
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The value of x in the equation = 5 is?
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