Quiz Discussion

If (2a+b)/(a+4b)=3 , then find the value of (a+b)/(a+2b)

• 1]

  10/9

• 2]

  1/9

• 3]

  11/7

• 4]

  8/7

The value of \({ \text{5}}\frac{1}{3} \div 1\frac{2}{9} \times \frac{1}{4}  \left( {10 + \frac{3}{{1 - \frac{1}{5}}}} \right)\)   = ?

• 1]

  15

• 2]

  67/25

• 3]

  128/11

• 4]

  128/99

\({{{{(469 + 174)}^2} - {{(469 - 174)}^2}} \over {(469 \times 174)}} = ?\)

• 1] 1
• 2] 4
• 3] 295
• 4] 643

If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\)       is = ?

• 1]

  1

• 2]

  \(\frac{{x + y + z}}{{a + b + c}}\)

• 3]

  \(\frac{{a + b + c}}{{x + y + z}}\)

• 4]

  Not possible to find

\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \)     is equal to = ?

• 1] 1
• 2] 4
• 3] 3
• 4] 2

If \(\left( {x + \frac{1}{x}} \right){ \text{ = 2,}}\)    then \(\left( {x - \frac{1}{x}} \right)\)   is equal to = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

Solve 4376 + 3209 - 1784 + 97 = 3125 + ?

• 1] 2713
• 2] 2743
• 3] 2773
• 4] 2793
• 5] 2737

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

• 1]

  \(17\frac{5}{{12}}\)

• 2]

  \(17\frac{8}{{17}}\)

• 3]

  \(20\frac{3}{{25}}\)

• 4]

  \(20\frac{{103}}{{250}}\)

There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

• 1] 20
• 2] 80
• 3] 100
• 4] 200
• 5] None of these

Simplify : \(\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?\)

• 1]

  100/101

• 2]

  90/101

• 3]

  20/101

• 4]

  101/100