Quiz Discussion

If \(x = \sqrt 3 { \text{ + }}\sqrt 2 { \text{,}}   \) then the value of \({x^3} - \frac{1}{{{x^3}}}\)  is?

• 1]

  \(10\sqrt 2 \)

• 2]

  \(14\sqrt 2\)

• 3]

  \(22\sqrt 2\)

• 4]

  \(8\sqrt 2\)

Given that ( 12 + 22 + 32 + .......... + 102 ) = 385, then the value of ( 22 + 32 + 42 + .......... + 202 ) is equal to = ?

• 1] 770
• 2] 1155
• 3] 1540
• 4] (385)2

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

• 1] 2
• 2] 8
• 3] 18
• 4] None of these

\(\left( {x + \frac{1}{x}} \right)\left( {x - \frac{1}{x}} \right)\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\left( {{x^2} + \frac{1}{{{x^2}}} + 1} \right)\)   is equal to ?

• 1]

  \({x^6} - \frac{1}{{{x^6}}}\)

• 2]

  \({x^8} - \frac{1}{{{x^8}}}\)

• 3]

  \({x^6} + \frac{1}{{{x^6}}}\)

• 4]

  \({x^8} + \frac{1}{{{x^8}}}\)

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

If the sum of two numbers is 22 and the sum of their squares is 404, then the product of two numbers is = ?

• 1] 40
• 2] 44
• 3] 80
• 4] 88

The value of x in the equation  = 5     is?

• 1] 21
• 2] 27
• 3] 35
• 4] 42

24.962 ÷ (34.11 ÷ 20.05) + 67.96 - 89.11 = ?

• 1] 884
• 2] 346
• 3] 252
• 4] 424
• 5] 366

\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \)     is equal to = ?

• 1] 1
• 2] 4
• 3] 3
• 4] 2

\(\frac{3}{7}{ \text{of }} 455 + \frac{5}{8}{ \text{of}}456 = ?\)

• 1] 448
• 2] 464
• 3] 476
• 4] 480
• 5] None of these