Quiz Discussion

\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\)     is equal to = ?

• 1] a - b
• 2] b - a
• 3] 1
• 4] 0

\({ \text{If }}\left[ {4 - \frac{5}{{1 + \frac{1}{{3 + \frac{1}{{2 + \frac{1}{4}}}}}}}} \right]\)  \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

• 1] 40 minutes
• 2] 45 minutes
• 3] 48 minutes
• 4] 36 minutes

Solve 4376 + 3209 - 1784 + 97 = 3125 + ?

• 1] 2713
• 2] 2743
• 3] 2773
• 4] 2793
• 5] 2737

If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ?

• 1] 0
• 2] 6xyz
• 3] 12xyz
• 4] xyz

The simplest value of \(\left( {\frac{1}{{\sqrt 9 - \sqrt 8 }} - \frac{1}{{\sqrt 8 - \sqrt 7 }} + \frac{1}{{\sqrt 7 - \sqrt 6 }} - \frac{1}{{\sqrt 6 - \sqrt 5 }}} \right)\)          is = ?

• 1]

  \(3 - \sqrt 5 \)

• 2]

  3

• 3]

  \(\sqrt 5 \)

• 4]

  \(\sqrt 5 - 3\)

\(1888 \div 32 \div 8 = ?\)

• 1] 7.375
• 2] 9.485
• 3] 29.5
• 4] 472
• 5] None of these

5² + 13²  – 11² = (?)³ – 52

• 1]

  6

• 2]

  3

• 3]

  4

• 4]

  5

If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\)       is = ?

• 1]

  1

• 2]

  \(\frac{{x + y + z}}{{a + b + c}}\)

• 3]

  \(\frac{{a + b + c}}{{x + y + z}}\)

• 4]

  Not possible to find

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

• 1] 2
• 2] 3
• 3] 6
• 4] 5

(? - 968) / 79 * 4 = 512

• 1] 10185
• 2] 10190
• 3] 11075
• 4] 11080
• 5] None of these