Quiz Discussion

If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \)    then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\)   = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

(4 / 5) × ? × (3 / 7) = (16 / 105)

• 1]

  8/9

• 2]

  5/7

• 3]

  4/9

• 4]

  3/7

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

• 1]

  3ad

• 2]

  3ac

• 3]

  2ad

• 4]

  2ab

\(\frac{3}{2} \times \frac{{11}}{5} \div \left( {\frac{{25}}{{44}} \times \frac{{11}}{5}} \right) \div \frac{{33}}{{15}} = ?\)

• 1]

  1/2

• 2]

  2/3

• 3]

  126/125

• 4]

  \(5\frac{{101}}{{125}}\)

• 5]

  None of these

Direction: In the question given below the given mathematical symbols are changed from '+' to '÷', '-' to '×', '÷' to '-' and from '×' to '+', then choose your answers from the following options.

• 1] -13
• 2] -3
• 3] 4
• 4] 7

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

• 1]

  \(17\frac{5}{{12}}\)

• 2]

  \(17\frac{8}{{17}}\)

• 3]

  \(20\frac{3}{{25}}\)

• 4]

  \(20\frac{{103}}{{250}}\)

Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?

• 1] a
• 2] b
• 3] c
• 4] All equal

\(\frac{{ \root 3 \of 8 }}{{\sqrt {16} }} \div \sqrt {\frac{{100}}{{49}}} \times \root 3 \of {125} \)     is equal to = ?

• 1]

  7

• 2]

  \(1\frac{3}{4}\)

• 3]

  \(\frac{7}{{1000}}\)

• 4]

  \(\frac{4}{7}\)

\(\frac{{{{\left( {3\frac{2}{3}} \right)}^2} - {{\left( {2\frac{1}{2}} \right)}^2}}}{{{{\left( {4\frac{3}{4}} \right)}^2} - {{\left( {3\frac{1}{3}} \right)}^2}}}\div\frac{{3\frac{2}{3} - 2\frac{1}{2}}}{{4\frac{3}{4} - 3\frac{1}{3}}}\)   = ?

• 1]

  37/97

• 2]

  74/97

• 3]

  \(1\frac{{23}}{{74}}\)

• 4]

  None of these

Solve this 9 3/7 - 6 4/7 - ? = 14 4/7

• 1]

  3/7

• 2]

  4/7

• 3]

  

• 4]