Quiz Discussion

When \(\left( {\frac{1}{2} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6}} \right) \) is divided by \(\left( {\frac{2}{5} - \frac{5}{9} + \frac{3}{5} - \frac{7}{{18}}} \right)\) then the result is = ?

• 1]

  \({ \text{5}}\frac{1}{{10}}\)

• 2]

  \({ \text{2}}\frac{1}{{18}}\)

• 3]

  \({ \text{3}}\frac{1}{6}\)

• 4]

  \({ \text{3}}\frac{3}{{10}}\)

The simplification of \(\left( {\frac{{75983 \times 75983 - 45983 \times 45983}}{{30000}}} \right)\)yields the result = ?

• 1] 121796
• 2] 121866
• 3] 121956
• 4] 121966

If \(\left( {a + \frac{1}{a}} \right) = 6,    then \left( {{a^4} + \frac{1}{{{a^4}}}} \right)\)   = ?

• 1] 1154
• 2] 1158
• 3] 1160
• 4] 1164

If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\)     then 12 + 32 + 52 + . . . . . + 172 is = ?

• 1] 969
• 2] 1785
• 3] 980
• 4] 1700

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

Direction: In the question given below the given mathematical symbols are changed from '+' to '÷', '-' to '×', '÷' to '-' and from '×' to '+', then choose your answers from the following options.

• 1] -13
• 2] -3
• 3] 4
• 4] 7

A teacher wants to arrange his students in an equal number of rows and columns. If there are 1369 students, the number of students in the last row are ?

• 1] 37
• 2] 33
• 3] 63
• 4] 47

\(\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}\)    is equal to = ?

• 1]

  \(\sqrt 6\)

• 2]

  \(\frac{{\sqrt 3 }}{2}\)

• 3]

  \(\frac{{\sqrt 2 }}{3}\)

• 4]

  \(\frac{{\sqrt 6 }}{2}\)

If 547.527/0.0082   then the value of 547527/82   is = ?

• 1]

  10x

• 2]

  100x

• 3]

  x/100

• 4]

  x/10

If a*b= ab/a+b, find the value of 3*(3*-1)

• 1]

  -1

• 2]

  1

• 3]

  3

• 4]

  -3