Quiz Discussion

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9

24.962 ÷ (34.11 ÷ 20.05) + 67.96 - 89.11 = ?

• 1] 884
• 2] 346
• 3] 252
• 4] 424
• 5] 366

1 - [5 - {2 + (- 5 + 6 - 2) 2}] is equal to:

• 1] -4
• 2] 2
• 3] 0
• 4] 2

If a*b= ab/a+b, find the value of 3*(3*-1)

• 1]

  -1

• 2]

  1

• 3]

  3

• 4]

  -3

Simplify : \(\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?\)

• 1]

  100/101

• 2]

  90/101

• 3]

  20/101

• 4]

  101/100

The Value of (\(\sqrt {6} + \sqrt {10} - \sqrt {21} - \sqrt {35}) × (\sqrt {6} - \sqrt {10} + \sqrt {21} - \sqrt {35}\)) = ?

• 1] 27
• 2] 18
• 3] 40
• 4] 10

\({ \text{If }}\left( {{n^r} - tn + \frac{1}{4}} \right)\)     be a perfect square, then the values of t are = ?

• 1] ± 2
• 2] 1, 2
• 3] 2, 3
• 4] ± 1

The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?

• 1] Rs. 325285
• 2] Rs. 439355
• 3] Rs. 550000
• 4] Cannot be determined
• 5] None of these

\(\left\{ {\left( {64 - 38} \right) \times 4} \right\} \div 13 = ?\)

• 1] 4
• 2] 1
• 3] 8
• 4] 2
• 5] 5

The value of \(\frac{{{{\left( {x - y} \right)}^3} + {{\left( {y - z} \right)}^3} + {{\left( {z - x} \right)}^3}}}{{{{\left( {{x^2} - {y^2}} \right)}^3} + {{\left( {{y^2} - {z^2}} \right)}^3} + {{\left( {{z^2} - {x^2}} \right)}^3}}}\)       is = ?

• 1]

  0

• 2]

  1

• 3]

  \({\left[ {2\left( {x + y + z} \right)} \right]^{ - 1}}\)

• 4]

  \({\left[ {\left( {x + y} \right)\left( {y + z} \right)\left( {z + x} \right)} \right]^{ - 1}}\)