Quiz Discussion

Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.

• 1] 3, 1
• 2] 3, 3
• 3] 4, 1
• 4] 5, 3

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

• 1]

  100

• 2]

  200/101

• 3]

  200

• 4]

  202/100

A teacher wants to arrange his students in an equal number of rows and columns. If there are 1369 students, the number of students in the last row are ?

• 1] 37
• 2] 33
• 3] 63
• 4] 47

Evaluated : \({{9\left| {3 - 5} \right| - 5\left| 4 \right| \div 10} \over { - 3\left( 5 \right) - 2 \times 4 \div 2}}\)

• 1]

  9/10

• 2]

  -8/17

• 3]

  -16/19

• 4]

  4/7

The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?

• 1] Rs. 325285
• 2] Rs. 439355
• 3] Rs. 550000
• 4] Cannot be determined
• 5] None of these

If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\)       is = ?

• 1]

  1

• 2]

  \(\frac{{x + y + z}}{{a + b + c}}\)

• 3]

  \(\frac{{a + b + c}}{{x + y + z}}\)

• 4]

  Not possible to find

The value of \(\frac{{{{\left( {x - y} \right)}^3} + {{\left( {y - z} \right)}^3} + {{\left( {z - x} \right)}^3}}}{{{{\left( {{x^2} - {y^2}} \right)}^3} + {{\left( {{y^2} - {z^2}} \right)}^3} + {{\left( {{z^2} - {x^2}} \right)}^3}}}\)       is = ?

• 1]

  0

• 2]

  1

• 3]

  \({\left[ {2\left( {x + y + z} \right)} \right]^{ - 1}}\)

• 4]

  \({\left[ {\left( {x + y} \right)\left( {y + z} \right)\left( {z + x} \right)} \right]^{ - 1}}\)

24.962 ÷ (34.11 ÷ 20.05) + 67.96 - 89.11 = ?

• 1] 884
• 2] 346
• 3] 252
• 4] 424
• 5] 366

421 ÷ 35 × 299.97 ÷ 25.05 = ?2

• 1] 22
• 2] 24
• 3] 28
• 4] 12
• 5] 18

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

• 1]

  \(17\frac{5}{{12}}\)

• 2]

  \(17\frac{8}{{17}}\)

• 3]

  \(20\frac{3}{{25}}\)

• 4]

  \(20\frac{{103}}{{250}}\)