Quiz Discussion

Solve this 9 3/7 - 6 4/7 - ? = 14 4/7

Course Name: Quantitative Aptitude

  • 1]

    3/7

  • 2]

    4/7

  • 3]

  • 4]

Solution
No Solution Present Yet

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# Quiz
1
Discuss

(755.0% of 523.0) / 777.0 = x

  • 1]

    6

  • 2]

    4

  • 3]

    3

  • 4]

    5

Solution
2
Discuss

\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \)     is equal to = ?

 

  • 1] 1
  • 2] 4
  • 3] 3
  • 4] 2
Solution
3
Discuss

The simplification of \(\frac{5}{{3 + \frac{3}{{1 - \frac{2}{3}}}}}, = ?\)

 

  • 1]

    5

  • 2]

    5/3

  • 3]

    5/12

  • 4]

    3/4

Solution
4
Discuss

The Value of (\(\sqrt {6} + \sqrt {10} - \sqrt {21} - \sqrt {35}) × (\sqrt {6} - \sqrt {10} + \sqrt {21} - \sqrt {35}\)) = ?

 

  • 1] 27
  • 2] 18
  • 3] 40
  • 4] 10
Solution
5
Discuss

\(\frac{{{{\left( {3\frac{2}{3}} \right)}^2} - {{\left( {2\frac{1}{2}} \right)}^2}}}{{{{\left( {4\frac{3}{4}} \right)}^2} - {{\left( {3\frac{1}{3}} \right)}^2}}}\div\frac{{3\frac{2}{3} - 2\frac{1}{2}}}{{4\frac{3}{4} - 3\frac{1}{3}}}\)   = ?

 

  • 1]

    37/97

  • 2]

    74/97

  • 3]

    \(1\frac{{23}}{{74}}\)

  • 4]

    None of these

Solution
6
Discuss

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

 

  • 1]

    \(1\frac{{11}}{{17}}\)

  • 2]

    \(1\frac{{5}}{{7}}\)

  • 3]

    \(1\frac{{6}}{{17}}\)

  • 4]

    \(1\frac{{21}}{{17}}\)

Solution
7
Discuss

If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\)     then 12 + 32 + 52 + . . . . . + 172 is = ?

 

  • 1] 969
  • 2] 1785
  • 3] 980
  • 4] 1700
Solution
8
Discuss

Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \)   = (?)3 + 141

 

  • 1] 5√5
  • 2] (125)2
  • 3] 25
  • 4] 5
  • 5] None of these
Solution
9
Discuss

(36.14)^2 – (21.28)^2 =?

  • 1]

    850

  • 2]

    860

  • 3]

    865

  • 4]

    853

Solution
10
Discuss

If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \)    then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\)   = ?

 

  • 1] 0
  • 2] 1
  • 3] 2
  • 4] 5
Solution
# Quiz