Quiz Discussion

\(\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}\)    is equal to = ?

• 1]

  \(\sqrt 6\)

• 2]

  \(\frac{{\sqrt 3 }}{2}\)

• 3]

  \(\frac{{\sqrt 2 }}{3}\)

• 4]

  \(\frac{{\sqrt 6 }}{2}\)

Simplify : \(1 - \left[ {1 - \left\{ {1 - \left( {1 - \overline {1 - 1} } \right)} \right\}} \right]\)

• 1] 0
• 2] 1
• 3] 2
• 4] 3
• 5] None of these

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

• 1] 2
• 2] 8
• 3] 18
• 4] None of these

\(6\frac{5}{6} \times 5\frac{1}{3} \times 17\frac{2}{3} \times 4\frac{1}{2} = ?\)

• 1]

  \(112\frac{1}{3}\)

• 2]

  \(116\frac{2}{3}\)

• 3]

  240

• 4]

  663

• 5]

  None of these

The number of pairs of natural numbers the difference of whose squares is 45 will be ?

• 1] 2
• 2] 3
• 3] 6
• 4] 5

If the sum of two numbers is 22 and the sum of their squares is 404, then the product of two numbers is = ?

• 1] 40
• 2] 44
• 3] 80
• 4] 88

\(\left\{ {\left( {64 - 38} \right) \times 4} \right\} \div 13 = ?\)

• 1] 4
• 2] 1
• 3] 8
• 4] 2
• 5] 5

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

• 1]

  \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

• 2]

  \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

• 3]

  \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

• 4]

  \(\frac{{{a^2} - {b^2}}}{{ab}}\)

Simplify : \(1 + {2 \over {1 + {3 \over {1 + {4 \over 5}}}}}\)

• 1]

  7/4

• 2]

  4/7

• 3]

  7/5

• 4]

  3/7

The difference of \({ \text{1}}\frac{3}{{16}}\) and its reciprocal is equal to = ?

• 1]

  \(1\frac{1}{8}\)

• 2]

  4/3

• 3]

  15/16

• 4]

  None of these