Quiz Discussion

Let 0 < x < 1, then the correct inequality is = ?

• 1]

  \(x < \sqrt x < {x^2}\)

• 2]

  \(\sqrt x < x < {x^2}\)

• 3]

  \({x^2} < x < \sqrt x \)

• 4]

  \(\sqrt x < {x^2} < x\)

The value of \({ \text{5}}\frac{1}{3} \div 1\frac{2}{9} \times \frac{1}{4}  \left( {10 + \frac{3}{{1 - \frac{1}{5}}}} \right)\)   = ?

• 1]

  15

• 2]

  67/25

• 3]

  128/11

• 4]

  128/99

Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?

• 1] 256
• 2] 432
• 3] 512
• 4] 640
• 5] None of these

\(\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}}\)

• 1] 0.1
• 2] 10
• 3] 102
• 4] 103

The difference of \({ \text{1}}\frac{3}{{16}}\) and its reciprocal is equal to = ?

• 1]

  \(1\frac{1}{8}\)

• 2]

  4/3

• 3]

  15/16

• 4]

  None of these

Assume that \(\sqrt {13} \) = 3.605(approximately) and \(\sqrt {130}\)  = 11.40(approximately) Find the value of: \(\sqrt {1.3}\) + \(\sqrt {1300}\)  + \(\sqrt {0.013}\)

• 1] 36.164
• 2] 36.304
• 3] 37.304
• 4] 37.164

If \(\left( {{a^4} + \frac{1}{{{a^4}}}} \right){ \text{ = 1154,}}\)     then the value of \(\left( {{a^3} + \frac{1}{{{a^3}}}} \right)\)   is = ?

• 1] 198
• 2] 200
• 3] 216
• 4] None of these

\({ \text{If }}\left( {{n^r} - tn + \frac{1}{4}} \right)\)     be a perfect square, then the values of t are = ?

• 1] ± 2
• 2] 1, 2
• 3] 2, 3
• 4] ± 1

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

• 1]

  100

• 2]

  200/101

• 3]

  200

• 4]

  202/100

25 * 3.250 + 50.40 / 24.0 = ?

• 1]

  75

• 2]

  80

• 3]

  77

• 4]

  83