Quiz Discussion

Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.

• 1] 3, 1
• 2] 3, 3
• 3] 4, 1
• 4] 5, 3

If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b}  \)    and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\)   = ?

• 1]

  \(\frac{{2ab}}{{{a^2} - {b^2}}}\)

• 2]

  \(\frac{{{a^2} - {b^2}}}{{2ab}}\)

• 3]

  \(\frac{{{a^2} + {b^2}}}{{2ab}}\)

• 4]

  \(\frac{{{a^2} - {b^2}}}{{ab}}\)

\(\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}}\)      = ?

• 1] 0.27
• 2] 0.4087
• 3] 0.73
• 4] 1

4848 / 24 * 11 - 222 = ?

• 1]

  200

• 2]

  2444

• 3]

  2000

• 4]

  \(115\frac{3}{8}\)

Direction: In the question given below the given mathematical symbols are changed from '+' to '÷', '-' to '×', '÷' to '-' and from '×' to '+', then choose your answers from the following options.

• 1] -13
• 2] -3
• 3] 4
• 4] 7

\(\left\{ {\left( {64 - 38} \right) \times 4} \right\} \div 13 = ?\)

• 1] 4
• 2] 1
• 3] 8
• 4] 2
• 5] 5

\(\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}\)    is equal to = ?

• 1]

  \(\sqrt 6\)

• 2]

  \(\frac{{\sqrt 3 }}{2}\)

• 3]

  \(\frac{{\sqrt 2 }}{3}\)

• 4]

  \(\frac{{\sqrt 6 }}{2}\)

98643 – 21748 = 51212 + ?

• 1]

  24383

• 2]

  24713

• 3]

  25683

• 4]

  26243

Simplify : \(\sqrt {3 + \frac{{33}}{{64}}} \div \sqrt {9 + \frac{1}{7}} \times  2\sqrt {3\frac{1}{9}}\)   = ?

• 1]

  45/256

• 2]

  \(1\frac{{17}}{{28}}\)

• 3]

  \(4\frac{3}{8}\)

• 4]

  \(2\frac{3}{{16}}\)

Evaluate : \({{ - {{\left( {4 - 6} \right)}^2} - 3\left( { - 2} \right) + \left| { - 6} \right|} \over {18 - 9 \div 3 \times 5}}\)

• 1]

  \(\frac{3}{8}\)

• 2]

  \(\frac{4}{7}\)

• 3]

  \(\frac{8}{3}\)

• 4]

  \(\frac{7}{4}\)