Quiz Discussion

Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?

• 1] a
• 2] b
• 3] c
• 4] All equal

If x + y = 2a, then the value of

• 1] 2
• 2] 0
• 3] -1
• 4] 1

( √5 – 2)^2 = x – √80

• 1]

  9

• 2]

  7

• 3]

  6

• 4]

  10

Find the value of \(\frac{{{{\left( {0.75} \right)}^3}}}{{1 - 0.75}} + \left[ {0.75 + {{\left( {0.75} \right)}^2} + 1} \right]\)

• 1] 4
• 2] 3
• 3] 2
• 4] 1

\(\left( {x + \frac{1}{x}} \right)\left( {x - \frac{1}{x}} \right)\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\left( {{x^2} + \frac{1}{{{x^2}}} + 1} \right)\)   is equal to ?

• 1]

  \({x^6} - \frac{1}{{{x^6}}}\)

• 2]

  \({x^8} - \frac{1}{{{x^8}}}\)

• 3]

  \({x^6} + \frac{1}{{{x^6}}}\)

• 4]

  \({x^8} + \frac{1}{{{x^8}}}\)

5 - [4 - {3 - (3 - 3 - 6)}] is equal to:

• 1] 10
• 2] 6
• 3] 4
• 4] 0

1559.95 - 7.99 × 24.96 - ?2 = 1154

• 1] 14
• 2] 24
• 3] 32
• 4] 18
• 5] 8

\(1\frac{3}{4} - 1\frac{1}{5} + 1\frac{5}{8} = ?\)

• 1]

  \(2\frac{7}{{40}}\)

• 2]

  \(3\frac{7}{{40}}\)

• 3]

  \(9\frac{5}{8}\)

• 4]

  \(10\frac{7}{8}\)

• 5]

  None of these

If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\)       is = ?

• 1]

  1

• 2]

  \(\frac{{x + y + z}}{{a + b + c}}\)

• 3]

  \(\frac{{a + b + c}}{{x + y + z}}\)

• 4]

  Not possible to find

\(\left\{ {\left( {64 - 38} \right) \times 4} \right\} \div 13 = ?\)

• 1] 4
• 2] 1
• 3] 8
• 4] 2
• 5] 5