Quiz Discussion

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

 

Course Name: Quantitative Aptitude

  • 1]

    \(17\frac{5}{{12}}\)

  • 2]

    \(17\frac{8}{{17}}\)

  • 3]

    \(20\frac{3}{{25}}\)

  • 4]

    \(20\frac{{103}}{{250}}\)

Solution
No Solution Present Yet

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# Quiz
1
Discuss

(4 / 5) × ? × (3 / 7) = (16 / 105)

  • 1]

    8/9

  • 2]

    5/7

  • 3]

    4/9

  • 4]

    3/7

Solution
2
Discuss

Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.

  • 1] 3, 1
  • 2] 3, 3
  • 3] 4, 1
  • 4] 5, 3
Solution
3
Discuss

If \(\frac{a}{b}{ \text{ + }}\frac{b}{a}{ \text{ = 2,}}\)    then the value of (a - b) is = ?

 

  • 1] 1
  • 2] 2
  • 3] -1
  • 4] 0
Solution
4
Discuss

\({ \text{If }}\left[ {4 - \frac{5}{{1 + \frac{1}{{3 + \frac{1}{{2 + \frac{1}{4}}}}}}}} \right]\)  \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

  • 1] 40 minutes
  • 2] 45 minutes
  • 3] 48 minutes
  • 4] 36 minutes
Solution
5
Discuss

Find the value of \(\sqrt {4 + \sqrt {44 + \sqrt {10000} } } \)

 

  • 1] 12
  • 2] 8
  • 3] 4
  • 4] -4
Solution
6
Discuss

A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:

  • 1] 30 birds
  • 2] 60 birds
  • 3] 72 birds
  • 4] 90 birds
  • 5] None of these
Solution
7
Discuss

Solve 4376 + 3209 - 1784 + 97 = 3125 + ?

  • 1] 2713
  • 2] 2743
  • 3] 2773
  • 4] 2793
  • 5] 2737
Solution
8
Discuss

If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\)     then 12 + 32 + 52 + . . . . . + 172 is = ?

 

  • 1] 969
  • 2] 1785
  • 3] 980
  • 4] 1700
Solution
9
Discuss

A millionaire bought a lot of hats 1/4 of which were brown. The millionaire sold 2/3 of the including 4/5 of the brown hats. What fraction of the unsold hats were brown ?

 

  • 1]

    1/60

  • 2]

    1/15

  • 3]

    3/20

  • 4]

    3/5

  • 5]

    3/4

Solution
10
Discuss

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

 

  • 1] 7.09
  • 2] 7.10
  • 3] 7.11
  • 4] 7.12
Solution
# Quiz