Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)
\(17\frac{5}{{12}}\)
\(17\frac{8}{{17}}\)
\(20\frac{3}{{25}}\)
\(20\frac{{103}}{{250}}\)
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Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)
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2
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\(\frac{3}{7}{ \text{of }} 455 + \frac{5}{8}{ \text{of}}456 = ?\)
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3
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If the sum of two numbers is 22 and the sum of their squares is 404, then the product of two numbers is = ?
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4
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The greatest 4 digit number which is a perfect square, is = ?
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5
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Evaluated : \({{9\left| {3 - 5} \right| - 5\left| 4 \right| \div 10} \over { - 3\left( 5 \right) - 2 \times 4 \div 2}}\)
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6
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(? - 968) / 79 * 4 = 512
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7
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A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
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8
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(98764 + 89881 + 99763 + 66342) ÷ (1186 + ? + 1040 + 1870) = 55
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9
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24.962 ÷ (34.11 ÷ 20.05) + 67.96 - 89.11 = ?
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10
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Solve 14 × 627 ÷ \(\sqrt {\left( {1089} \right)} \) = (?)3 + 141
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