Quiz Discussion

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

• 1] 2
• 2] 8
• 3] 18
• 4] None of these

Find the value of \(\sqrt {248 + \sqrt {52 + \sqrt {144} } } = ?\)

• 1]

  -16

• 2]

  \(\pm 16\)

• 3]

  16

• 4]

  16.2

Number of digits in the square root of 62478078 is = ?

• 1] 4
• 2] 5
• 3] 6
• 4] 3

\({ \text{If }}x = \frac{1}{{2 + \frac{1}{2}}}{ \text{ then }}\frac{1}{x} = ?\)

• 1]

  2/5

• 2]

  5/2

• 3]

  3/5

• 4]

  1/2

Simplify : \({ \text{8}}\frac{1}{2} - \left[ {3\frac{1}{4} + \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)

• 1]

  \(4\frac{1}{2}\)

• 2]

  \(4\frac{1}{6}\)

• 3]

  \(9\frac{1}{2}\)

• 4]

  \(\frac{2}{9}\)

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

• 1]

  3ad

• 2]

  3ac

• 3]

  2ad

• 4]

  2ab

If \(\left( {4{b^2} + \frac{1}{{{b^2}}}} \right){ \text{ = 2,}} \)    then \(\left( {8{b^3} + \frac{1}{{{b^3}}}} \right)\)   = ?

• 1] 0
• 2] 1
• 3] 2
• 4] 5

\({{{{(469 + 174)}^2} - {{(469 - 174)}^2}} \over {(469 \times 174)}} = ?\)

• 1] 1
• 2] 4
• 3] 295
• 4] 643

(36.14)^2 – (21.28)^2 =?

• 1]

  850

• 2]

  860

• 3]

  865

• 4]

  853

(98764 + 89881 + 99763 + 66342) ÷ (1186 + ? + 1040 + 1870) = 55

• 1] 2254
• 2] 2354
• 3] 2368
• 4] 2404
• 5] None of these