Quiz Discussion

( √5 – 2)^2 = x – √80

• 1]

  9

• 2]

  7

• 3]

  6

• 4]

  10

Number of digits in the square root of 62478078 is = ?

• 1] 4
• 2] 5
• 3] 6
• 4] 3

3.325 + 3.012 + 0.660 + 31.151 + 0.251 = ?

• 1]

  40.019

• 2]

  35.055

• 3]

  37.514

• 4]

  38.399

\({{{{(469 + 174)}^2} - {{(469 - 174)}^2}} \over {(469 \times 174)}} = ?\)

• 1] 1
• 2] 4
• 3] 295
• 4] 643

1 - [5 - {2 + (- 5 + 6 - 2) 2}] is equal to:

• 1] -4
• 2] 2
• 3] 0
• 4] 2

\(\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}}\)      = ?

• 1] 0.27
• 2] 0.4087
• 3] 0.73
• 4] 1

A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?

• 1] 45
• 2] 60
• 3] 75
• 4] 90
• 5] None of these

\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \)     is equal to = ?

• 1] 1
• 2] 4
• 3] 3
• 4] 2

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9

Simplify : \(\frac{{ - \frac{1}{2} - \frac{2}{3} + \frac{4}{5} - \frac{1}{3} + \frac{1}{5} + \frac{3}{4}}}{{\frac{1}{2} + \frac{2}{3} - \frac{4}{3} + \frac{1}{3} - \frac{1}{5} - \frac{4}{5}}}\)

• 1]

  -3/10

• 2]

  -10/3

• 3]

  -2

• 4]

  1