Quiz Discussion

\(\left( {\frac{{\sqrt {625} }}{{11}} \times \frac{{14}}{{\sqrt {25} }} \times \frac{{11}}{{\sqrt {196} }}} \right){\kern 1pt} \)     is equal to :

• 1] 5
• 2] 6
• 3] 8
• 4] 11

One-fourth of the sum of prime numbers, greater than 4 but less than 16, is the square of = ?

• 1] 3
• 2] 4
• 3] 5
• 4] 7

\(\left( {\frac{{2 + \sqrt 3 }}{{2 - \sqrt 3 }} + \frac{{2 - \sqrt 3 }}{{2 + \sqrt 3 }} + \frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}} \right) \)     simplifies to = ?

• 1]

  \(16 - \sqrt 3 \)

• 2]

  \(4 - \sqrt 3 \)

• 3]

  \(2 - \sqrt 3 \)

• 4]

  \(2 + \sqrt 3 \)

1250 oranges were distributed among a group of girls of a class. Each girl got twice as many oranges as the number of girls in that group. The number of girls in the group was = ?

• 1] 25
• 2] 45
• 3] 50
• 4] 100

If \(\sqrt 5 = 2.236{ \text{,}}\)   then the value of \(\frac{1}{{\sqrt 5 }} \) is = ?

• 1] 0.367
• 2] 0.447
• 3] 0.745
• 4] None of these

Which number can replace both the question marks in the equation =?

• 1]

  12

• 2]

  7

• 3]

  

• 4]

  None of these

If = the value of x is = ?

• 1] 52
• 2] 58
• 3] 62
• 4] 68

If y = 5,   then what is the value of \(10y\sqrt {{y^3} - {y^2}} \)   = ?

• 1]

  \(50\sqrt 2 \)

• 2]

  100

• 3]

  \(200\sqrt 5 \)

• 4]

  500

\(\sqrt {\frac{{25}}{{81}} - \frac{1}{9}} = ?\)

• 1]

  2/3

• 2]

  4/9

• 3]

  16/81

• 4]

  25/81

  is equal to ?

• 1] 0.9
• 2] 0.99
• 3] 9
• 4] 99