98643 – 21748 = 51212 + ?
24383
24713
25683
26243
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1
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A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
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2
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The value of \({ \text{5}}\frac{1}{3} \div 1\frac{2}{9} \times \frac{1}{4} \left( {10 + \frac{3}{{1 - \frac{1}{5}}}} \right)\) = ?
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3
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The difference of \({ \text{1}}\frac{3}{{16}}\) and its reciprocal is equal to = ?
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4
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If \(\frac{{x + 1}}{{x - 1}}{ \text{ = }}\frac{a}{b} \) and \(\frac{{1 - y}}{{1 + y}}{ \text{ = }}\frac{b}{a}{ \text{,}} \) then the value of \(\frac{{x - y}}{{1 + xy}}\) = ?
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5
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Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ?
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6
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Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)
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7
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1559.95 - 7.99 × 24.96 - ?2 = 1154
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8
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Solve : 128.43 + 30.21 + ? = 173
Solution |
9
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\(\sqrt {\frac{{{{\left( {0.03} \right)}^2} + {{\left( {0.21} \right)}^2} + {{\left( {0.065} \right)}^2}}}{{{{\left( {0.003} \right)}^2} + {{\left( {0.021} \right)}^2} + {{\left( {0.0065} \right)}^2}}}}\)
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10
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24.962 ÷ (34.11 ÷ 20.05) + 67.96 - 89.11 = ?
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