Quiz Discussion

(4 / 5) × ? × (3 / 7) = (16 / 105)

• 1]

  8/9

• 2]

  5/7

• 3]

  4/9

• 4]

  3/7

25 * 3.250 + 50.40 / 24.0 = ?

• 1]

  75

• 2]

  80

• 3]

  77

• 4]

  83

Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)

• 1]

  1/2

• 2]

  4

• 3]

  2

• 4]

  1/4

\(\frac{{ \root 3 \of 8 }}{{\sqrt {16} }} \div \sqrt {\frac{{100}}{{49}}} \times \root 3 \of {125} \)     is equal to = ?

• 1]

  7

• 2]

  \(1\frac{3}{4}\)

• 3]

  \(\frac{7}{{1000}}\)

• 4]

  \(\frac{4}{7}\)

Solve \({ \text{1}}\frac{4}{5} + 20 - 280 \div 25 = ?\)

• 1]

  \(8\frac{1}{5}\)

• 2]

  \(9\frac{1}{2}\)

• 3]

  \(11\frac{1}{2}\)

• 4]

  \(10\frac{3}{5}\)

• 5]

  \(12\frac{1}{5}\)

(98764 + 89881 + 99763 + 66342) ÷ (1186 + ? + 1040 + 1870) = 55

• 1] 2254
• 2] 2354
• 3] 2368
• 4] 2404
• 5] None of these

853 + ? / 17 = 1000

• 1] 2482
• 2] 2499
• 3] 2516
• 4] 16147
• 5] None of these

When \(\left( {\frac{1}{2} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6}} \right) \) is divided by \(\left( {\frac{2}{5} - \frac{5}{9} + \frac{3}{5} - \frac{7}{{18}}} \right)\) then the result is = ?

• 1]

  \({ \text{5}}\frac{1}{{10}}\)

• 2]

  \({ \text{2}}\frac{1}{{18}}\)

• 3]

  \({ \text{3}}\frac{1}{6}\)

• 4]

  \({ \text{3}}\frac{3}{{10}}\)

If \(\root 3 \of {{3^n}} { \text{ = 27,}}\)  then the value of n is = ?

• 1] 9
• 2] 6
• 3] 1
• 4] 3

There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

• 1] 20
• 2] 80
• 3] 100
• 4] 200
• 5] None of these