Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.
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If a*b= ab/a+b, find the value of 3*(3*-1)
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2
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The value (1001)3 is = ?
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3
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Assume that \(\sqrt {13} \) = 3.605(approximately) and \(\sqrt {130}\) = 11.40(approximately) Find the value of: \(\sqrt {1.3}\) + \(\sqrt {1300}\) + \(\sqrt {0.013}\)
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4
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( √5 – 2)^2 = x – √80
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5
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\({ \text{If }}\left[ {4 - \frac{5}{{1 + \frac{1}{{3 + \frac{1}{{2 + \frac{1}{4}}}}}}}} \right]\) \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
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Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)
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(? - 968) / 79 * 4 = 512
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8
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The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
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If the expression \({ \text{2}}\frac{1}{2}{ \text{ of }}\frac{3}{4} \times \frac{1}{2} \div \frac{3}{2} + \frac{1}{2} \div \frac{3}{2}\left[ {\frac{2}{3} - \frac{1}{2}{ \text{ of }}\frac{2}{3}} \right]\) is simplified, we get -
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A body of 7300 troops is formed of 4 battalions so that 1/2 of the first, 2/3 of the second, 3/4 of the third and 4/5 of the fourth are all composed of the same number of men. How many men are there in the second battalion?
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