Quiz Discussion

The 3rd and 6th term of an arithmetic progression are 13 and -5 respectively. What is the 11th term?

Course Name: Quantitative Aptitude

  • 1] -29
  • 2] -41
  • 3] -47
  • 4] -35
Solution
No Solution Present Yet

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# Quiz
1
Discuss

The 3rd and 7th term of an arithmetic progression are -9 and 11 respectively. What is the 15th term?

  • 1]

    28

  • 2]

    87

  • 3]

    51

  • 4]

    17

Solution
2
Discuss

If the sums of n terms of two arithmetic progressions are in the ratio \(\frac{{3n + 5}}{{5n + 7}}\)   then their nth terms are in the ration

 

  • 1]

    \(\frac{{3n - 1}}{{5n - 1}}\)

  • 2]

    \(\frac{{3n + 1}}{{5n + 1}}\)

  • 3]

    \(\frac{{5n + 1}}{{3n + 1}}\)

  • 4]

    \(\frac{{5n - 1}}{{3n - 1}}\)

Solution
3
Discuss

After striking the floor, a rubber ball rebounds to 4/5th of the height from which it has fallen. Find the total distance that it travels before coming to rest if it has been gently dropped from a height of 120 metres.

  • 1] 540 m
  • 2] 960 m
  • 3] 1080 m
  • 4] 1020 m
  • 5] 1120 m
Solution
4
Discuss

The nth term of an A.P., the sum of whose n terms is Sn, is

  • 1] Sn + Sn - 1
  • 2] Sn - Sn - 1
  • 3] Sn + Sn + 1
  • 4] Sn - Sn + 1
Solution
5
Discuss

A boy agrees to work at the rate of one rupee on the first day, two rupees on the second day, and four rupees on third day and so on. How much will the boy get if he started working on the 1st of February and finishes on the 20th of February?

  • 1] 220
  • 2] 220 -1
  • 3] 219 -1
  • 4] 219
  • 5] None of these
Solution
6
Discuss

The 7th and 12th term of an arithmetic progression are -15 and 5 respectively. What is the 16th term?

  • 1] 25
  • 2] 29
  • 3] 21
  • 4] 33
Solution
7
Discuss

What is the sum of the first 12 terms of an arithmetic progression if the first term is -19 and last term is 36?

  • 1] 192
  • 2] 230
  • 3] 102
  • 4] 214
Solution
8
Discuss

If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164 ?

  • 1] 26th
  • 2] 27th
  • 3] 28th
  • 4] None of these
Solution
9
Discuss

A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :

  • 1]

    \(\frac{{{3^{10}}}}{2}\)

  • 2]

    310 - 210

  • 3]

    243 × (35 -1)

  • 4]

    310 - 25

  • 5]

    None of these

Solution
10
Discuss

(1) + (1 + 1) + (1 + 1 + 1) + ....... + (1 + 1 + 1 + ...... n - 1 times) = ......

  • 1]

    \(\frac{{n\left( {n + 1} \right)}}{2}\)

  • 2]

    \(\frac{{n\left( {n - 1} \right)}}{2}\)

  • 3]

    \({n^2}\)

  • 4]

    n

Solution
# Quiz