Quiz Discussion

Let S denotes the sum of n terms of an A.P. whose first term is a. If the common difference d is given by d = Sn – k Sn-1 + Sn-2 then k =

Course Name: Quantitative Aptitude

  • 1]

    1

  • 2]

    2

  • 3]

    3

  • 4]

    4

Solution
No Solution Present Yet

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# Quiz
1
Discuss

The first and last term of an A.P. is a and l respectively. If S is the sum of all the terms of the A.P. and the common difference is given by \(\frac{{{l^2} - {a^2}}}{{k - \left( {l + a} \right)}}\)   then k = ?

 

  • 1] S
  • 2] 2S
  • 3] 3S
  • 4] None of these
Solution
2
Discuss

Two A.P.’s have the same common difference. The first term of one of these is 8 and that of the other is 3. The difference between their 30th terms is

  • 1] 11
  • 2] 3
  • 3] 8
  • 4] 5
Solution
3
Discuss

If a + 1, 2a + 1, 4a - 1 are in A.P., then the value of a is:

  • 1] 1
  • 2] 2
  • 3] 3
  • 4] 4
Solution
4
Discuss

If sum of n terms of an A.P. is 3n2 + 5n and Tm = 164 then m =

  • 1]

    26

  • 2]

    27

  • 3]

    28

  • 4]

    None Of This

Solution
5
Discuss

Find the nth term of the following sequence :

  • 1]

    5(10n - 1)

  • 2]

    5n(10n - 1)

  • 3]

    \(\frac{5}{9} \times \left( {{{10}^n} - 1} \right)\)

  • 4]

    \({\left( {\frac{5}{9}} \right)^n} \times \left( {{{10}^n} - 1} \right)\)

Solution
6
Discuss

If the sums of n terms of two arithmetic progressions are in the ratio \(\frac{{3n + 5}}{{5n + 7}}\)   then their nth terms are in the ration

 

  • 1]

    \(\frac{{3n - 1}}{{5n - 1}}\)

  • 2]

    \(\frac{{3n + 1}}{{5n + 1}}\)

  • 3]

    \(\frac{{5n + 1}}{{3n + 1}}\)

  • 4]

    \(\frac{{5n - 1}}{{3n - 1}}\)

Solution
7
Discuss

Which term of the A.P. 92, 88, 84, 80, ...... is 0?

  • 1] 23
  • 2] 32
  • 3] 22
  • 4] 24
Solution
8
Discuss

The number of terms of the A.P. 3, 7, 11, 15, ....... to be taken so that the sum is 406 is

  • 1]

    5

  • 2]

    10

  • 3]

    12

  • 4]

    14

Solution
9
Discuss

For an A.P. if a25 - a20 = 45, then d equals to:

  • 1] 9
  • 2] -9
  • 3] 18
  • 4] 23
Solution
10
Discuss

The common difference of the A.P. \(\frac{1}{{2b}} \frac{{1 - 6b}}{{2b}}  \frac{{1 - 12b}}{{2b}}\)   . . . . . is

 

  • 1] 2b
  • 2] -2b
  • 3] 3
  • 4] -3
Solution
# Quiz