Quiz Discussion

If the first term of an A.P. is 2 and common difference is 4, then the sum of its 40 term is

Course Name: Quantitative Aptitude

  • 1] 3200
  • 2] 1600
  • 3] 200
  • 4] 2800
Solution
No Solution Present Yet

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# Quiz
1
Discuss

The 3rd and 7th term of an arithmetic progression are -9 and 11 respectively. What is the 15th term?

  • 1] 28
  • 2] 87
  • 3] 51
  • 4] 17
Solution
2
Discuss

The first and last term of an A.P. is a and l respectively. If S is the sum of all the terms of the A.P. and the common difference is given by \(\frac{{{l^2} - {a^2}}}{{k - \left( {l + a} \right)}}\)   then k = ?

 

  • 1] S
  • 2] 2S
  • 3] 3S
  • 4] None of these
Solution
3
Discuss

What is the sum of the first 17 terms of an arithmetic progression if the first term is -20 and last term is 28?

  • 1] 68
  • 2] 156
  • 3] 142
  • 4] 242
Solution
4
Discuss

What is the sum of the first 9 terms of an arithmetic progression if the first term is 7 and last term is 55?

  • 1] 219
  • 2] 279
  • 3] 231
  • 4] 137
Solution
5
Discuss

A piece of equipment cost a certain factory 6,00,000. If it depreciates in value, 15% the first year, 13.5% the next year, 12% the third year, and so on, what will be its value at the end of 10 years, all percentages applying to the original cost?

  • 1] Rs. 2,00,000
  • 2] Rs. 1,05,000
  • 3] Rs. 4,05,000
  • 4] Rs. 6,50,000
Solution
6
Discuss

The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is

  • 1] 600
  • 2] 765
  • 3] 640
  • 4] 680
  • 5] 690
Solution
7
Discuss

If Sn denote the sum of the first n terms of an A.P. If S2n = 3Sn , then S3n : Sn is equal to

  • 1] 4
  • 2] 6
  • 3] 8
  • 4] 10
Solution
8
Discuss

The common difference of the A.P. \(\frac{1}{3}, \frac{{1 - 3b}}{3} , \frac{{1 - 6b}}{3}\)   . . . . . . is

 

  • 1]

    \(\frac{1}{3}\)

  • 2]

    \( - \frac{1}{3}\)

  • 3]

    -b

  • 4]

    b

Solution
9
Discuss

A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :

  • 1]

    \(\frac{{{3^{10}}}}{2}\)

  • 2]

    310 - 210

  • 3]

    243 × (35 -1)

  • 4]

    310 - 25

  • 5]

    None of these

Solution
10
Discuss

If 18th and 11th term of an A.P. are in the ratio 3 : 2, then its 21st and 5th terms are in the ratio

  • 1] 3 : 2
  • 2] 3 : 1
  • 3] 1 : 3
  • 4] 2 : 3
Solution
# Quiz