If the first term of an A.P. is 2 and common difference is 4, then the sum of its 40 term is
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1
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The 3rd and 7th term of an arithmetic progression are 9 and 11 respectively. What is the 15th term?
Solution 
2
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The first and last term of an A.P. is a and l respectively. If S is the sum of all the terms of the A.P. and the common difference is given by \(\frac{{{l^2}  {a^2}}}{{k  \left( {l + a} \right)}}\) then k = ?
Solution 
3
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What is the sum of the first 17 terms of an arithmetic progression if the first term is 20 and last term is 28?
Solution 
4
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What is the sum of the first 9 terms of an arithmetic progression if the first term is 7 and last term is 55?
Solution 
5
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A piece of equipment cost a certain factory 6,00,000. If it depreciates in value, 15% the first year, 13.5% the next year, 12% the third year, and so on, what will be its value at the end of 10 years, all percentages applying to the original cost?
Solution 
6
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The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is
Solution 
7
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If Sn denote the sum of the first n terms of an A.P. If S2n = 3Sn , then S3n : Sn is equal to
Solution 
8
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The common difference of the A.P. \(\frac{1}{3}, \frac{{1  3b}}{3} , \frac{{1  6b}}{3}\) . . . . . . is
Solution 
9
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A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :
Solution 
10
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If 18th and 11th term of an A.P. are in the ratio 3 : 2, then its 21st and 5th terms are in the ratio
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