Quiz Discussion

Simplify : \(\frac{{\frac{5}{3} \times \frac{7}{{51}}{ \text{ of }}\frac{17}{5} - \frac{1}{3}}}{{\frac{2}{9} \times \frac{5}{7}{ \text{ of }}\frac{{28}}{5} - \frac{2}{3}}}{\kern 1pt} {\kern 1pt} = ?\)

• 1]

  1/3

• 2]

  1/6

• 3]

  4

• 4]

  2

\(\frac{{225}}{{836}} \times \frac{{152}}{{245}} \div 1\frac{{43}}{{77}} = ?\)

• 1]

  6/49

• 2]

  6/11

• 3]

  3/28

• 4]

  1/7

• 5]

  None of these

Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.

• 1] 3, 1
• 2] 3, 3
• 3] 4, 1
• 4] 5, 3

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

• 1]

  \(1\frac{{11}}{{17}}\)

• 2]

  \(1\frac{{5}}{{7}}\)

• 3]

  \(1\frac{{6}}{{17}}\)

• 4]

  \(1\frac{{21}}{{17}}\)

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

• 1]

  3ad

• 2]

  3ac

• 3]

  2ad

• 4]

  2ab

853 + ? / 17 = 1000

• 1] 2482
• 2] 2499
• 3] 2516
• 4] 16147
• 5] None of these

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

If \(\frac{1}{3} + \frac{1}{2} + \frac{1}{x}{ \text{ = 4}}\)     then x = ?

• 1]

  5/16

• 2]

  6/19

• 3]

  18/5

• 4]

  24/11

\(\left\{ {\left( {\sqrt {72} - \sqrt {18} } \right) \div \sqrt {12} } \right\}\)    is equal to = ?

• 1]

  \(\sqrt 6\)

• 2]

  \(\frac{{\sqrt 3 }}{2}\)

• 3]

  \(\frac{{\sqrt 2 }}{3}\)

• 4]

  \(\frac{{\sqrt 6 }}{2}\)

A body of 7300 troops is formed of 4 battalions so that 1/2 of the first, 2/3 of the second, 3/4 of the third and 4/5 of the fourth are all composed of the same number of men. How many men are there in the second battalion?

• 1] 1500
• 2] 1600
• 3] 1800
• 4] 2400