Quiz Discussion

What number must be added to the expression 16a2 - 12a to make a perfect square ?

• 1]

  9/4

• 2]

  11/2

• 3]

  13/2

• 4]

  16

\(\left( {x + \frac{1}{x}} \right)\left( {x - \frac{1}{x}} \right)\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\left( {{x^2} + \frac{1}{{{x^2}}} + 1} \right)\)   is equal to ?

• 1]

  \({x^6} - \frac{1}{{{x^6}}}\)

• 2]

  \({x^8} - \frac{1}{{{x^8}}}\)

• 3]

  \({x^6} + \frac{1}{{{x^6}}}\)

• 4]

  \({x^8} + \frac{1}{{{x^8}}}\)

(36.14)^2 – (21.28)^2 =?

• 1]

  850

• 2]

  860

• 3]

  865

• 4]

  853

Simplify : \({ \text{10}}\frac{1}{8}{ \text{ of }}\frac{{12}}{{15}} \div \frac{{35}}{{36}}{ \text{ of }}\frac{{20}}{{49}}\)

• 1]

  \(17\frac{5}{{12}}\)

• 2]

  \(17\frac{8}{{17}}\)

• 3]

  \(20\frac{3}{{25}}\)

• 4]

  \(20\frac{{103}}{{250}}\)

The simplification of \(\frac{5}{{3 + \frac{3}{{1 - \frac{2}{3}}}}}, = ?\)

• 1]

  5

• 2]

  5/3

• 3]

  5/12

• 4]

  3/4

Assume that \(\sqrt {13} \) = 3.605(approximately) and \(\sqrt {130}\)  = 11.40(approximately) Find the value of: \(\sqrt {1.3}\) + \(\sqrt {1300}\)  + \(\sqrt {0.013}\)

• 1] 36.164
• 2] 36.304
• 3] 37.304
• 4] 37.164

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

• 1] 7.09
• 2] 7.10
• 3] 7.11
• 4] 7.12

853 + ? / 17 = 1000

• 1] 2482
• 2] 2499
• 3] 2516
• 4] 16147
• 5] None of these

Find the value of \(\frac{{{{\left( {0.75} \right)}^3}}}{{1 - 0.75}} + \left[ {0.75 + {{\left( {0.75} \right)}^2} + 1} \right]\)

• 1] 4
• 2] 3
• 3] 2
• 4] 1

Let 0 < x < 1, then the correct inequality is = ?

• 1]

  \(x < \sqrt x < {x^2}\)

• 2]

  \(\sqrt x < x < {x^2}\)

• 3]

  \({x^2} < x < \sqrt x \)

• 4]

  \(\sqrt x < {x^2} < x\)