Quiz Discussion

(36.14)^2 – (21.28)^2 =?

Course Name: Quantitative Aptitude

  • 1]

    850

  • 2]

    860

  • 3]

    865

  • 4]

    853

Solution
No Solution Present Yet

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# Quiz
1
Discuss

If \(\frac{1}{3} + \frac{1}{2} + \frac{1}{x}{ \text{ = 4}}\)     then x = ?

 

  • 1]

    5/16

  • 2]

    6/19

  • 3]

    18/5

  • 4]

    24/11

Solution
2
Discuss

If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\)     then 12 + 32 + 52 + . . . . . + 172 is = ?

 

  • 1] 969
  • 2] 1785
  • 3] 980
  • 4] 1700
Solution
3
Discuss

The difference of \({ \text{1}}\frac{3}{{16}}\) and its reciprocal is equal to = ?

 

  • 1]

    \(1\frac{1}{8}\)

  • 2]

    4/3

  • 3]

    15/16

  • 4]

    None of these

Solution
4
Discuss

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

 

  • 1]

    100

  • 2]

    200/101

  • 3]

    200

  • 4]

    202/100

Solution
5
Discuss

\({{{{(469 + 174)}^2} - {{(469 - 174)}^2}} \over {(469 \times 174)}} = ?\)

 

  • 1] 1
  • 2] 4
  • 3] 295
  • 4] 643
Solution
6
Discuss

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

 

  • 1] 0
  • 2] 1
  • 3] 3
  • 4] 9
Solution
7
Discuss

(? - 968) / 79 * 4 = 512

 

  • 1] 10185
  • 2] 10190
  • 3] 11075
  • 4] 11080
  • 5] None of these
Solution
8
Discuss

\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\)     is equal to = ?

 

  • 1] a - b
  • 2] b - a
  • 3] 1
  • 4] 0
Solution
9
Discuss

If (a+b+2c+3d)(a-b-2c+3d)=(a-b+2c-3d)(a+b-2c-3d), then 2bcis equal to?

  • 1]

    3ad

  • 2]

    3ac

  • 3]

    2ad

  • 4]

    2ab

Solution
10
Discuss

\(\frac{{38 \times 38 \times 38 + 34 \times 34 \times 34 + 28 \times 28 \times 28 - 38 \times 34 \times 84}}{{38 \times 38 + 34 \times 34 + 28 \times 28 - 38 \times 34 - 34 \times 28 - 38 \times 28}}\)           is equal to = ?

 

  • 1] 24
  • 2] 32
  • 3] 44
  • 4] 100
Solution
# Quiz