Quiz Discussion

\(\frac{{20 + 8 \times 0.5}}{{20 - ?}}{ \text{ = 12}}\)     Find the value in place of (?)

 

Course Name: Quantitative Aptitude

  • 1] 2
  • 2] 8
  • 3] 18
  • 4] None of these
Solution
No Solution Present Yet

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# Quiz
1
Discuss

If \(\left( {{a^4} + \frac{1}{{{a^4}}}} \right){ \text{ = 1154,}}\)     then the value of \(\left( {{a^3} + \frac{1}{{{a^3}}}} \right)\)   is = ?

 

  • 1] 198
  • 2] 200
  • 3] 216
  • 4] None of these
Solution
2
Discuss

Simplify : \(1 + {2 \over {1 + {3 \over {1 + {4 \over 5}}}}}\)

 

  • 1]

    7/4

  • 2]

    4/7

  • 3]

    7/5

  • 4]

    3/7

Solution
3
Discuss

The sum of \(\sqrt {0.01} + \sqrt {0.81} + \sqrt {1.21} + \sqrt {0.0009} = ?\)

 

  • 1] 2.1
  • 2] 2.13
  • 3] 2.03
  • 4] 2.11
Solution
4
Discuss

421 ÷ 35 × 299.97 ÷ 25.05 = ?2

  • 1] 22
  • 2] 24
  • 3] 28
  • 4] 12
  • 5] 18
Solution
5
Discuss

\(\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}}\)      = ?

 

  • 1] 0.27
  • 2] 0.4087
  • 3] 0.73
  • 4] 1
Solution
6
Discuss

\(\frac{{ \root 3 \of 8 }}{{\sqrt {16} }} \div \sqrt {\frac{{100}}{{49}}} \times \root 3 \of {125} \)     is equal to = ?

 

  • 1]

    7

  • 2]

    \(1\frac{3}{4}\)

  • 3]

    \(\frac{7}{{1000}}\)

  • 4]

    \(\frac{4}{7}\)

Solution
7
Discuss

Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.

  • 1] 3, 1
  • 2] 3, 3
  • 3] 4, 1
  • 4] 5, 3
Solution
8
Discuss

Find the value of \(\frac{{{{\left( {0.75} \right)}^3}}}{{1 - 0.75}} + \left[ {0.75 + {{\left( {0.75} \right)}^2} + 1} \right]\)

 

  • 1] 4
  • 2] 3
  • 3] 2
  • 4] 1
Solution
9
Discuss

What is \(\frac{{\frac{7}{8} \times \frac{7}{8} + \frac{5}{6} \times \frac{5}{6} + \frac{7}{8} \times \frac{5}{3}}}{{\frac{7}{8} \times \frac{7}{8} - \frac{5}{6} \times \frac{5}{6}}}\)     equal to ?

 

  • 1]

    41/24

  • 2]

    1/24

  • 3]

    41

  • 4]

    None of these

Solution
10
Discuss

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

 

  • 1] 7.09
  • 2] 7.10
  • 3] 7.11
  • 4] 7.12
Solution
# Quiz