Quiz Discussion

A sum of Rs. 1360 has been divided among A, B and C such that A gets 2/3 of what B gets and B gets 1/4 of what C gets. B's share is:

• 1] Rs. 120
• 2] Rs. 160
• 3] Rs. 240
• 4] Rs. 300
• 5] None of these

The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?

• 1] Rs. 325285
• 2] Rs. 439355
• 3] Rs. 550000
• 4] Cannot be determined
• 5] None of these

A millionaire bought a lot of hats 1/4 of which were brown. The millionaire sold 2/3 of the including 4/5 of the brown hats. What fraction of the unsold hats were brown ?

• 1]

  1/60

• 2]

  1/15

• 3]

  3/20

• 4]

  3/5

• 5]

  3/4

If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ?

• 1] 0
• 2] 6xyz
• 3] 12xyz
• 4] xyz

Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)

• 1]

  1/2

• 2]

  4

• 3]

  2

• 4]

  1/4

\(\frac{{ \root 3 \of 8 }}{{\sqrt {16} }} \div \sqrt {\frac{{100}}{{49}}} \times \root 3 \of {125} \)     is equal to = ?

• 1]

  7

• 2]

  \(1\frac{3}{4}\)

• 3]

  \(\frac{7}{{1000}}\)

• 4]

  \(\frac{4}{7}\)

\(\frac{3}{2} \times \frac{{11}}{5} \div \left( {\frac{{25}}{{44}} \times \frac{{11}}{5}} \right) \div \frac{{33}}{{15}} = ?\)

• 1]

  1/2

• 2]

  2/3

• 3]

  126/125

• 4]

  \(5\frac{{101}}{{125}}\)

• 5]

  None of these

The sum of \(\sqrt {0.01} + \sqrt {0.81} + \sqrt {1.21} + \sqrt {0.0009} = ?\)

• 1] 2.1
• 2] 2.13
• 3] 2.03
• 4] 2.11

When \(\left( {\frac{1}{2} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6}} \right) \) is divided by \(\left( {\frac{2}{5} - \frac{5}{9} + \frac{3}{5} - \frac{7}{{18}}} \right)\) then the result is = ?

• 1]

  \({ \text{5}}\frac{1}{{10}}\)

• 2]

  \({ \text{2}}\frac{1}{{18}}\)

• 3]

  \({ \text{3}}\frac{1}{6}\)

• 4]

  \({ \text{3}}\frac{3}{{10}}\)

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9