If \(\left( {x + \frac{1}{x}} \right) = 3,\)    then \(\left( {{x^2} + \frac{1}{{{x^2}}}} \right)\)   is = ?

• 1]

  10/3

• 2]

  82/9

• 3]

  7

• 4]

  11

Given that =3.605 and =11.40 , Find the value of  + +

• 1]

  36.164

• 2]

  36.304

• 3]

  37.164

• 4]

  37.304

\(\sqrt {\frac{{4\frac{1}{7} - 2\frac{1}{4}}}{{3\frac{1}{2} + 1\frac{1}{7}}} \div \frac{1}{{2 + \frac{1}{{2 + \frac{1}{{5 - \frac{1}{5}}}}}}}} \)     is equal to = ?

• 1] 1
• 2] 4
• 3] 3
• 4] 2

Simplify : \(\frac{{\frac{5}{3} \times \frac{7}{{51}}{ \text{ of }}\frac{17}{5} - \frac{1}{3}}}{{\frac{2}{9} \times \frac{5}{7}{ \text{ of }}\frac{{28}}{5} - \frac{2}{3}}}{\kern 1pt} {\kern 1pt} = ?\)

• 1]

  1/3

• 2]

  1/6

• 3]

  4

• 4]

  2

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

• 1] 0
• 2] 1
• 3] 3
• 4] 9

Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)

• 1]

  0.006

• 2]

  1/6

• 3]

  0.6

• 4]

  6

572.0 / 26 * 12 – 200 = (2)^x

• 1]

  8

• 2]

  4

• 3]

  6

• 4]

  10

The simplified value of \(\frac{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) - \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)\left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}}{{\left( {1 + \frac{1}{{1 + \frac{1}{{100}}}}} \right) + \left( {1 - \frac{1}{{1 + \frac{1}{{100}}}}} \right)}} = ?\)

• 1]

  100

• 2]

  200/101

• 3]

  200

• 4]

  202/100

If x = a + m, y = b + m, z = c + m, then the value of \(\frac{{{x^2} + {y^2} + {z^2} - yz - zx - xy}}{{{a^2} + {b^2} + {c^2} - ab - bc - ca}}\)       is = ?

• 1]

  1

• 2]

  \(\frac{{x + y + z}}{{a + b + c}}\)

• 3]

  \(\frac{{a + b + c}}{{x + y + z}}\)

• 4]

  Not possible to find

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

• 1]

  \(1\frac{{11}}{{17}}\)

• 2]

  \(1\frac{{5}}{{7}}\)

• 3]

  \(1\frac{{6}}{{17}}\)

• 4]

  \(1\frac{{21}}{{17}}\)