Quiz Discussion

The Value of (\(\sqrt {6} + \sqrt {10} - \sqrt {21} - \sqrt {35}) × (\sqrt {6} - \sqrt {10} + \sqrt {21} - \sqrt {35}\)) = ?

 

Course Name: Quantitative Aptitude

  • 1] 27
  • 2] 18
  • 3] 40
  • 4] 10
Solution
No Solution Present Yet

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# Quiz
1
Discuss

Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)

 

  • 1]

    1/2

  • 2]

    4

  • 3]

    2

  • 4]

    1/4

Solution
2
Discuss

3/5 of 4/7 of 5/9 of 21/24 of 504 = ?

  • 1]

    63

  • 2]

    39

  • 3]

    96

  • 4]

    84

Solution
3
Discuss

\(\frac{{{{\left( {469 + 174} \right)}^2} - {{\left( {469 - 174} \right)}^2}}}{{469 \times 174}} \)      = ?

 

  • 1] 2
  • 2] 4
  • 3] 295
  • 4] 643
Solution
4
Discuss

5907 – 1296 / 144 = x * 8.0

  • 1]

    700.05

  • 2]

    705.25

  • 3]

    751.54

  • 4]

    737.25

Solution
5
Discuss

(9.0 / 2 * 27 / 9 ) / (18/7.5 * 5.0 / 4) = ?

  • 1]

    5.5

  • 2]

    4.0

  • 3]

    4.5

  • 4]

    3.0

Solution
6
Discuss

If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\)     then 12 + 32 + 52 + . . . . . + 172 is = ?

 

  • 1] 969
  • 2] 1785
  • 3] 980
  • 4] 1700
Solution
7
Discuss

If \(\left( {a + \frac{1}{a}} \right) = 6,    then \left( {{a^4} + \frac{1}{{{a^4}}}} \right)\)   = ?

 

  • 1] 1154
  • 2] 1158
  • 3] 1160
  • 4] 1164
Solution
8
Discuss

If (2a+b)/(a+4b)=3 , then find the value of (a+b)/(a+2b)

  • 1]

    10/9

  • 2]

    1/9

  • 3]

    11/7

  • 4]

    8/7

Solution
9
Discuss

If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\)   + \(\sqrt {{ \text{0}}{ \text{.4096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.004096}}}\)   + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\)     up to two place of decimals is = ?

 

  • 1] 7.09
  • 2] 7.10
  • 3] 7.11
  • 4] 7.12
Solution
10
Discuss

If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ?

  • 1] 0
  • 2] 6xyz
  • 3] 12xyz
  • 4] xyz
Solution
# Quiz