The Value of (\(\sqrt {6} + \sqrt {10} - \sqrt {21} - \sqrt {35}) × (\sqrt {6} - \sqrt {10} + \sqrt {21} - \sqrt {35}\)) = ?
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Simplify : \({{{5 \over 3} \times {7 \over {51}}{ \text{ of }}{{17} \over 5} - {1 \over 3}} \over {{2 \over 9} \times {5 \over 7}{ \text{ of }}{{28} \over 5} - {2 \over 3}}}\)
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3/5 of 4/7 of 5/9 of 21/24 of 504 = ?
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\(\frac{{{{\left( {469 + 174} \right)}^2} - {{\left( {469 - 174} \right)}^2}}}{{469 \times 174}} \) = ?
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5907 – 1296 / 144 = x * 8.0
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(9.0 / 2 * 27 / 9 ) / (18/7.5 * 5.0 / 4) = ?
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6
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If 12 + 22 + 32 + . . . . . + p2 = \(\left[ {\frac{{{ \text{p}}\left( {{ \text{p}} + 1} \right)\left( {2{ \text{p}} + 1} \right)}}{6}} \right]{ \text{,}}\) then 12 + 32 + 52 + . . . . . + 172 is = ?
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If \(\left( {a + \frac{1}{a}} \right) = 6, then \left( {{a^4} + \frac{1}{{{a^4}}}} \right)\) = ?
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If (2a+b)/(a+4b)=3 , then find the value of (a+b)/(a+2b)
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If \(\sqrt {{ \text{4096}}}\) = 64, then the value of \(\sqrt {{ \text{40}}{ \text{.96}}}\) + \(\sqrt {{ \text{0}}{ \text{.4096}}}\) + \(\sqrt {{ \text{0}}{ \text{.004096}}}\) + \(\sqrt {{ \text{0}}{ \text{.00004096}}}\) up to two place of decimals is = ?
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If x + y + z = 0, then x3 + y3 + z3 + 3xyz is equal to = ?
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