A body of 7300 troops is formed of 4 battalions so that 1/2 of the first, 2/3 of the second, 3/4 of the third and 4/5 of the fourth are all composed of the same number of men. How many men are there in the second battalion?
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Supply the two missing figures in order indicated by x and y in the given equation, the fractions being in their lowest terms.
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\(\frac{{{{\left( {0.73} \right)}^3} + {{\left( {0.27} \right)}^3}}}{{{{\left( {0.73} \right)}^2} + {{\left( {0.27} \right)}^2} - 0.73 \times 0.27}}\) = ?
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(755.0% of 523.0) / 777.0 = x
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\({ \text{If }}\left( {{n^r} - tn + \frac{1}{4}} \right)\) be a perfect square, then the values of t are = ?
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The cost of 5 pendants and 8 chains is Rs. 145785. What would be the cost of 15 pendants and 24 chains ?
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The simplification of \(\frac{5}{{3 + \frac{3}{{1 - \frac{2}{3}}}}}, = ?\)
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\(\left\{ {\left( {64 - 38} \right) \times 4} \right\} \div 13 = ?\)
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The number of pairs of natural numbers the difference of whose squares is 45 will be ?
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Find the value of \(\frac{{{{\left( {0.75} \right)}^3}}}{{1 - 0.75}} + \left[ {0.75 + {{\left( {0.75} \right)}^2} + 1} \right]\)
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Solve : 128.43 + 30.21 + ? = 173
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