A and B working together completed a job in 5 days. If A works twice as efficiently as he actually did and B works \(\frac{1}{3}\) of actual efficiency, the work would have been completed in 3 days. Find the for A to complete the job alone.
\(6\frac{1}{2}\)
\(6\frac{1}{4}\)
\(6\frac{3}{4}\)
\(12\frac{1}{2}\)
None of these
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A and B together can do a job in 2 days; B and C can do it in 4 days; A and C in \({ \text{2}}\frac{2}{5}\) days. The number of days required for A to do the job alone is = ?
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5
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10
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