Quiz Discussion

\(\frac{{ \root 3 \of 8 }}{{\sqrt {16} }} \div \sqrt {\frac{{100}}{{49}}} \times \root 3 \of {125} \)     is equal to = ?

 

Course Name: Quantitative Aptitude

  • 1]

    7

  • 2]

    \(1\frac{3}{4}\)

  • 3]

    \(\frac{7}{{1000}}\)

  • 4]

    \(\frac{4}{7}\)

Solution
No Solution Present Yet

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# Quiz
1
Discuss

\(\frac{{{{\left( {469 + 174} \right)}^2} - {{\left( {469 - 174} \right)}^2}}}{{469 \times 174}} \)      = ?

 

  • 1] 2
  • 2] 4
  • 3] 295
  • 4] 643
Solution
2
Discuss

If \(\left( {{a^4} + \frac{1}{{{a^4}}}} \right){ \text{ = 1154,}}\)     then the value of \(\left( {{a^3} + \frac{1}{{{a^3}}}} \right)\)   is = ?

 

  • 1] 198
  • 2] 200
  • 3] 216
  • 4] None of these
Solution
3
Discuss

The simplification of \(\frac{5}{{3 + \frac{3}{{1 - \frac{2}{3}}}}}, = ?\)

 

  • 1]

    5

  • 2]

    5/3

  • 3]

    5/12

  • 4]

    3/4

Solution
4
Discuss

\(\frac{1}{{1 + {2^{a - b}}}} + \frac{1}{{1 + {2^{b - a}}}}\)     is equal to = ?

 

  • 1] a - b
  • 2] b - a
  • 3] 1
  • 4] 0
Solution
5
Discuss

If the sum of two numbers is 22 and the sum of their squares is 404, then the product of two numbers is = ?

  • 1] 40
  • 2] 44
  • 3] 80
  • 4] 88
Solution
6
Discuss

\({ \text{If }}\left[ {4 - \frac{5}{{1 + \frac{1}{{3 + \frac{1}{{2 + \frac{1}{4}}}}}}}} \right]\)  \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

  • 1] 40 minutes
  • 2] 45 minutes
  • 3] 48 minutes
  • 4] 36 minutes
Solution
7
Discuss

Simplify : \(1 + {1 \over {1 + {2 \over {2 + {3 \over {1 + {4 \over 5}}}}}}}\)

 

  • 1]

    \(1\frac{{11}}{{17}}\)

  • 2]

    \(1\frac{{5}}{{7}}\)

  • 3]

    \(1\frac{{6}}{{17}}\)

  • 4]

    \(1\frac{{21}}{{17}}\)

Solution
8
Discuss

Solve this 9 3/7 - 6 4/7 - ? = 14 4/7

  • 1]

    3/7

  • 2]

    4/7

  • 3]

  • 4]

Solution
9
Discuss

Find the value of * in the following. \({ \text{1}}\frac{2}{3} \div \frac{2}{7} \times \frac{*}{7} = 1\frac{1}{4} \times \frac{2}{3} \div \frac{1}{6}\)

 

  • 1]

    0.006

  • 2]

    1/6

  • 3]

    0.6

  • 4]

    6

Solution
10
Discuss

If \(\frac{p}{a} + \frac{q}{b} + \frac{r}{c} = 1\)     and \(\frac{a}{p} + \frac{b}{q} + \frac{c}{r} = 0\)     where a, b, c, p, q, r are non-zero real numbers, then \(\frac{{{p^2}}}{{{a^2}}} + \frac{{{q^2}}}{{{b^2}}} + \frac{{{r^2}}}{{{c^2}}}\)    is equal to = ?

 

  • 1] 0
  • 2] 1
  • 3] 3
  • 4] 9
Solution
# Quiz