Quiz Discussion

The two geometric means between the number 1 and 64 are

Course Name: Quantitative Aptitude

  • 1]

    8 and 16

  • 2]

    2 and 16

  • 3]

    4 and 8

  • 4]

    4 and 16

Solution
No Solution Present Yet

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# Quiz
1
Discuss

After striking the floor, a rubber ball rebounds to 4/5th of the height from which it has fallen. Find the total distance that it travels before coming to rest if it has been gently dropped from a height of 120 metres.

  • 1] 540 m
  • 2] 960 m
  • 3] 1080 m
  • 4] 1020 m
  • 5] 1120 m
Solution
2
Discuss

In an A.P., if d = -4, n = 7, an = 4, then a is

  • 1] 6
  • 2] 7
  • 3] 20
  • 4] 28
Solution
3
Discuss

If the sum of the series 2 + 5 + 8 + 11 … is 60100, then the number of terms are

  • 1]

    100

  • 2]

    150

  • 3]

    200

  • 4]

    250

Solution
4
Discuss

In an A.P., if d = -4, n = 7, an = 4, then a is

  • 1]

    6

  • 2]

    7

  • 3]

    20

  • 4]

    28

Solution
5
Discuss

Sum of n terms of the series \(\sqrt 2   +   \sqrt 8   +   \sqrt {18}   +   \sqrt {32}   +  \) ....... is

 

  • 1]

    \(\frac{{n\left( {n + 1} \right)}}{2}\)

  • 2]

    \(2n\left( {n + 1} \right)\)

  • 3]

    \(\frac{{n\left( {n + 1} \right)}}{{\sqrt 2 }}\)

  • 4]

    1

Solution
6
Discuss

Find the nth term of the following sequence :

  • 1]

    5(10n - 1)

  • 2]

    5n(10n - 1)

  • 3]

    \(\frac{5}{9} \times \left( {{{10}^n} - 1} \right)\)

  • 4]

    \({\left( {\frac{5}{9}} \right)^n} \times \left( {{{10}^n} - 1} \right)\)

Solution
7
Discuss

If the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273, then the third term is :

  • 1] 13
  • 2] 9
  • 3] 21
  • 4] 17
Solution
8
Discuss

Find the nth term of the following sequence :
5 + 55 + 555 + . . . . Tn

  • 1]

     

    5(10n - 1) 

  • 2]

     

    5n(10n - 1)

  • 3]

    5/9×(10n−1)

       

  • 4]

    (5/9)n×(10n−1)

Solution
9
Discuss

Find the 15th term of the sequence 20, 15, 10 . . . . .

  • 1] -45
  • 2] -55
  • 3] -50
  • 4] 0
Solution
10
Discuss

(1) + (1 + 1) + (1 + 1 + 1) + ....... + (1 + 1 + 1 + ...... n - 1 times) = ......

  • 1]

    \(\frac{{n\left( {n + 1} \right)}}{2}\)

  • 2]

    \(\frac{{n\left( {n - 1} \right)}}{2}\)

  • 3]

    \({n^2}\)

  • 4]

    n

Solution
# Quiz