Quiz Discussion

If S1 is the sum of an arithmetic progression of ‘n’ odd number of terms and S2 is the sum of the terms of the series in odd places, then \(\frac{{{S_1}}}{{{S_2}}}\)

 

Course Name: Quantitative Aptitude

  • 1]

    \(\frac{{2n}}{{n + 1}}\)

  • 2]

    \(\frac{n}{{n + 1}}\)

  • 3]

    \(\frac{{n + 1}}{{2n}}\)

  • 4]

    \(\frac{{n - 1}}{n}\)

Solution
No Solution Present Yet

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# Quiz
1
Discuss

The first and last term of an A.P. is a and l respectively. If S is the sum of all the terms of the A.P. and the common difference is given by \(\frac{{{l^2} - {a^2}}}{{k - \left( {l + a} \right)}}\)   then k = ?

 

  • 1] S
  • 2] 2S
  • 3] 3S
  • 4] None of these
Solution
2
Discuss

How many 2-digit positive integers are divisible by 4 or 9?

  • 1]

    32

  • 2]

    22

  • 3]

    34

  • 4]

    30

Solution
3
Discuss

Find the 15th term of the sequence 20, 15, 10 . . . . .

  • 1] -45
  • 2] -55
  • 3] -50
  • 4] 0
Solution
4
Discuss

The 2nd and 6th term of an arithmetic progression are 8 and 20 respectively. What is the 20th term?

  • 1] 56
  • 2] 65
  • 3] 59
  • 4] 62
Solution
5
Discuss

If the fifth term of a GP is 81 and first term is 16, what will be the 4th term of the GP?

  • 1] 36
  • 2] 18
  • 3] 54
  • 4] 24
  • 5] 27
Solution
6
Discuss

If log 2, log (2x -1) and log (2x + 3) are in A.P, then x is equal to ___

  • 1]

     

    5/2

  • 2]

    log25

  • 3]

    log32

  • 4]

     

    3/2

Solution
7
Discuss

The 3rd and 6th term of an arithmetic progression are 13 and -5 respectively. What is the 11th term?

  • 1] -29
  • 2] -41
  • 3] -47
  • 4] -35
Solution
8
Discuss

Consider an infinite G.P. with first term a and common ratio r, its sum is 4 and the second term is 3/4, then

  • 1]

    a = 7/4, r = 3/7

  • 2]

    a = 2, r = 3/8

  • 3]

    a = 3, r = 1/4

  • 4]

    a = 3/2, r = ½

Solution
9
Discuss

Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.

  • 1] 5
  • 2] 6
  • 3] 4
  • 4] 3
  • 5] 7
Solution
10
Discuss

A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :

  • 1]

    \(\frac{{{3^{10}}}}{2}\)

  • 2]

    310 - 210

  • 3]

    243 × (35 -1)

  • 4]

    310 - 25

  • 5]

    None of these

Solution
# Quiz