Quiz Discussion

Find the value of the following expression upto four places of decimals.

\(\left[ {1 + \frac{1}{{1 \times 2}} + \frac{1}{{1 \times 2 \times 4}} + \frac{1}{{1 \times 2 \times 4 \times 8}} + \frac{1}{{1 \times 2 \times 4 \times 8 \times 16}}} \right]\)

• 1] 1.6414
• 2] 1.6415
• 3] 1.6416
• 4] 1.6428

The value of \(\frac{{489.1375 \times 0.0483 \times 1.956}}{{0.0873 \times 92.581 \times 99.749}}\)     is closest to:

• 1] 0.006
• 2] 0.06
• 3] 0.6
• 4] 6

Solve : \(7\frac{1}{2} -  \left[ {2\frac{1}{4} ÷ \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)       = ?

• 1]

  2/9

• 2]

  \(4\frac{1}{2}\)

• 3]

  \(9\frac{1}{2}\)

• 4]

  \(1\frac{77}{228}\)

What is the difference between the biggest and the smallest fraction among 2/3, 3/4, 4/5, and 5/6 ?

• 1]

  1/6

• 2]

  1/12

• 3]

  1/20

• 4]

  1/30

  = ?

• 1] 0.4
• 2] 1.2
• 3] 1.4
• 4] 4

[(?)2 + (18)2] ÷ 125 = 3.56

• 1] 11
• 2] 12
• 3] 14
• 4] 15
• 5] None of these

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?

• 1] 2010
• 2] 2011
• 3] 2012
• 4] 2013

The value of \(\frac{{3.157 \times 4126 \times 3.198}}{{63.972 \times 2835.121}}\)    is closest to :

• 1] 0.002
• 2] 0.02
• 3] 0.2
• 4] 2

Given, 168 × 32 = 5376 , then 5.376 ÷ 16.8 is equal to :

• 1] 0.032
• 2] 0.32
• 3] 3.2
• 4] 32

If 47.2506=4A+7/B+2C+5/D +6E then the value of 5A+3B+6C+D+3E is

• 1]

  53.6003

• 2]

  53.603

• 3]

  153.6003

• 4]

  213.003