Quiz Discussion

58.621 - 13.829 - 7.302 - 1.214 = ?

• 1] 31.254
• 2] 35.272
• 3] 36.276
• 4] 37.281
• 5] None of these

If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?

• 1] 0.172
• 2] 1.72
• 3] 17.2
• 4] 172

The correct expression of \(6.\overline {46}\) in the fractional form is:

• 1]

  646/99

• 2]

  64640/1000

• 3]

  640/100

• 4]

  640/99

534.596 + 61.472 - 496.708 = ? + 27.271

• 1] 62.069
• 2] 72.089
• 3] 126.631
• 4] 132.788
• 5] None of these

The value of (1.25)³ - 2.25 (1.25)² + 3.75 (0.75)² - (0.75)³ is :

• 1]

  1

• 2]

  1/2

• 3]

  1/4

• 4]

  1/8

Find the value of the following expression upto four places of decimals.

\(\left[ {1 + \frac{1}{{1 \times 2}} + \frac{1}{{1 \times 2 \times 4}} + \frac{1}{{1 \times 2 \times 4 \times 8}} + \frac{1}{{1 \times 2 \times 4 \times 8 \times 16}}} \right]\)

• 1] 1.6414
• 2] 1.6415
• 3] 1.6416
• 4] 1.6428

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?

• 1]

  2010

• 2]

  2011

• 3]

  2012

• 4]

  2013

      is equal to :

• 1]

  1/2

• 2]

  1/3

• 3]

  2

• 4]

  10

0.002 x 0.5 = ?

• 1] 0.0001
• 2] 0.001
• 3] 0.01
• 4] 0.1

The value of \(\frac{{{{\left( {0.96} \right)}^3} - {{\left( {0.1} \right)}^3}}}{{{{\left( {0.96} \right)}^2} + 0.096 + {{\left( {0.1} \right)}^2}}}{ \text{is}}:\)

• 1] 0.86
• 2] 0.95
• 3] 0.97
• 4] 1.06