Quiz Discussion

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?

• 1]

  2010

• 2]

  2011

• 3]

  2012

• 4]

  2013

Which of the following is equal to 3.14 x 106 ?

• 1] 314
• 2] 3140
• 3] 3140000
• 4] None of these

\(\frac{{5 \times 1.6 - 2 \times 1.4}}{{1.3}} = ?\)

• 1] 0.4
• 2] 1.2
• 3] 1.4
• 4] 4

What is difference between biggest and smallest fraction among 2/3, 3/4, 4/5 and 5/6

• 1]

  2/5

• 2]

  3/5

• 3]

  1/6

• 4]

  1/7

Which of the following are in descending order of their value ?

• 1]

  \(\frac{1}{3},\frac{2}{5},\frac{3}{7},\frac{4}{5},\frac{5}{6},\frac{6}{7}\)

• 2]

  \(\frac{1}{3},\frac{2}{5},\frac{3}{5},\frac{4}{7},\frac{5}{6},\frac{6}{7}\)

• 3]

  \(\frac{1}{3},\frac{2}{5},\frac{3}{5},\frac{4}{6},\frac{5}{7},\frac{6}{7}\)

• 4]

  \(\frac{6}{7},\frac{5}{6},\frac{4}{5},\frac{3}{7},\frac{2}{5},\frac{1}{3}\)

The number 0.121212 ... in the form p/q is equal to

• 1]

  4/11

• 2]

  2/11

• 3]

  4/33

• 4]

  2/33

Solve : \(7\frac{1}{2} -  \left[ {2\frac{1}{4} ÷ \left\{ {1\frac{1}{4} - \frac{1}{2}\left( {1\frac{1}{2} - \frac{1}{3} - \frac{1}{6}} \right)} \right\}} \right]\)       = ?

• 1]

  2/9

• 2]

  \(4\frac{1}{2}\)

• 3]

  \(9\frac{1}{2}\)

• 4]

  \(1\frac{77}{228}\)

\(\frac{{{{\left( {0.013} \right)}^3} + 0.000000343}}{{{{\left( {0.013} \right)}^2} - 0.000091 + 0.000049}} = \,?\) = ?

• 1] 0.002
• 2] 0.020
• 3] 0.021
• 4] 0.023

When 0.232323..... is converted into a fraction, then the result is:

• 1]

  1/5

• 2]

  2/9

• 3]

  23/99

• 4]

  23/100

3889 + 12.952 - ? = 3854.002

• 1] 47.095
• 2] 47.752
• 3] 47.932
• 4] 47.95