Quiz Discussion

The cube root of .000216 is:

• 1] .6
• 2] .06
• 3] 77
• 4] 87

\({\left[ {{{\left( {\sqrt {81} } \right)}^2}} \right]^2} = {\left( ? \right)^2}\)

• 1] 8
• 2] 9
• 3] 4096
• 4] 6561
• 5] None of these

A man born in the first half of the nineteenth century was x years old in the year x2. He was born in ?

• 1] 1806
• 2] 1812
• 3] 1825
• 4] 1836

The square root of 64009 is:

• 1] 253
• 2] 347
• 3] 363
• 4] 803

\(\frac{1}{{\left( {\sqrt 9 - \sqrt 8 } \right)}} -   \frac{1}{{\left( {\sqrt 8 - \sqrt 7 } \right)}} +   \frac{1}{{\left( {\sqrt 7 - \sqrt 6 } \right)}} -   \frac{1}{{\left( {\sqrt 6 - \sqrt 5 } \right)}} +   \frac{1}{{\left( {\sqrt 5 - \sqrt 4 } \right)}}\)   is equal to ?

• 1]

  0

• 2]

  1/3

• 3]

  1

• 4]

  5

If y = 5,   then what is the value of \(10y\sqrt {{y^3} - {y^2}} \)   = ?

• 1]

  \(50\sqrt 2 \)

• 2]

  100

• 3]

  \(200\sqrt 5 \)

• 4]

  500

Square root of 64009 is

• 1]

  253

• 2]

  347

• 3]

  363

• 4]

  803

If \(x = 3 + \sqrt 8 ,   \) then \({x^2} + \frac{1}{{{x^2}}}\) is equal to = ?

• 1] 30
• 2] 34
• 3] 36
• 4] 38

Solved \( \root 4 \of {{{\left( {625} \right)}^3}} = ?\)

• 1]

  \( \root 3 \of {1875} \)

• 2]

  25

• 3]

  125

• 4]

  None of these

\(\left( {\frac{{2 + \sqrt 3 }}{{2 - \sqrt 3 }} + \frac{{2 - \sqrt 3 }}{{2 + \sqrt 3 }} + \frac{{\sqrt 3 - 1}}{{\sqrt 3 + 1}}} \right) \)     simplifies to = ?

• 1]

  \(16 - \sqrt 3 \)

• 2]

  \(4 - \sqrt 3 \)

• 3]

  \(2 - \sqrt 3 \)

• 4]

  \(2 + \sqrt 3 \)