Quiz Discussion

If 1537* is a perfect square, then the digit which replace * is = ?

Course Name: Quantitative Aptitude

  • 1] 2
  • 2] 4
  • 3] 5
  • 4] 6
Solution
No Solution Present Yet

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# Quiz
1
Discuss

Solved \( \root 4 \of {{{\left( {625} \right)}^3}} = ?\)

 

  • 1]

    \( \root 3 \of {1875} \)

  • 2]

    25

  • 3]

    125

  • 4]

    None of these

Solution
2
Discuss

If \(a = \frac{{\sqrt 5 + 1}}{{\sqrt 5 - 1}}   \) and \(b = \frac{{\sqrt 5 - 1}}{{\sqrt 5 + 1}},\)   the value of \(\left( {\frac{{{a^2} + ab + {b^2}}}{{{a^2} - ab + {b^2}}}} \right)\)   is ?

 

  • 1]

    3/4

  • 2]

    4/3

  • 3]

    3/5

  • 4]

    5/3

Solution
3
Discuss

Which number can replace both the question marks in the equation =?

 

  • 1]

    12

  • 2]

    7

  • 3]

  • 4]

    None of these

Solution
4
Discuss

\(\sqrt {0.2} = ?\)

 

  • 1] 0.02
  • 2] 0.2
  • 3] 0.447
  • 4] 0.632
Solution
5
Discuss

What percentage of the numbers from 1 to 50 have squares that end in the digit 1 ?

  • 1] 1%
  • 2] 5%
  • 3] 10%
  • 4] 11%
  • 5] 20%
Solution
6
Discuss

The number of perfect square numbers between 50 and 1000 is = ?

  • 1] 21
  • 2] 22
  • 3] 23
  • 4] 24
Solution
7
Discuss

If \(\sqrt 5 = 2.236{ \text{,}}\)   then the value of \(\frac{1}{{\sqrt 5 }} \) is = ?

 

  • 1] 0.367
  • 2] 0.447
  • 3] 0.745
  • 4] None of these
Solution
8
Discuss

\(\left( {\frac{{\sqrt {625} }}{{11}} \times \frac{{14}}{{\sqrt {25} }} \times \frac{{11}}{{\sqrt {196} }}} \right){\kern 1pt} \)     is equal to :

 

  • 1] 5
  • 2] 6
  • 3] 8
  • 4] 11
Solution
9
Discuss

Find the cube root of 2744.

  • 1]

    14

  • 2]

    13

  • 3]

    12

  • 4]

    11

Solution
10
Discuss

What should come in place of both x in the equation \(\frac{x}{{\sqrt {128} }} = \frac{{\sqrt {162} }}{x}\)

 

  • 1] 12
  • 2] 14
  • 3] 144
  • 4] 196
Solution
# Quiz